Select Paginator并使用join选择

在我当前的ZF2 projet中，我使用Paginator，但遇到了一个问题

当我将Paginator与select联接一起使用时，我无法显示不属于我的Servicegroup对象的object元素

# Create a new Select object
      $Select = new Select();
      $Select->from('t_service_group')
             ->join('t_user_group', 't_user_group.user_group_id = t_service_group.fk_user_group_id')
             ->order('service_group_name ASC');

      # Create a new result set
      $resultSetPrototype = new ResultSet();
      $resultSetPrototype->setArrayObjectPrototype(new ServiceGroup());

      # Create a new pagination adapter object
      $paginatorAdapter = new DbSelect(
        # Our configured select object
        $Select,
        # The adapter to run it against
        $this->tableGateway->getAdapter(),
        # The result set to hydrate
        $resultSetPrototype
      );
      $paginator = new Paginator($paginatorAdapter);
      return $paginator;

您知道如何使用paginator而不使用：

 setArrayObjectPrototype(new ServiceGroup());

谢谢大家的帮助 致意

编辑

如果在查询分页器中使用带有join的select查询。你必须做到：

     # Create a new Select object
      $Select = new Select();
      $Select->from('t_service_group')
             ->join('t_user_group', 't_user_group.user_group_id = t_service_group.fk_user_group_id')
             ->order('service_group_name ASC');

      # Create a new result set
      $resultSetPrototype = new ResultSet();
#      $resultSetPrototype->setArrayObjectPrototype(new ServiceGroup());

      # Create a new pagination adapter object
      $paginatorAdapter = new DbSelect(
        # Our configured select object
        $Select,
        # The adapter to run it against
        $this->tableGateway->getAdapter(),
        # The result set to hydrate
        $resultSetPrototype
      );
      $paginator = new Paginator($paginatorAdapter);
      return $paginator;

---

您不需要设置resultsetprototype，而是使用默认的结果集原型，它将填充从该行返回的所有值