Sequelize.js 具有多个模型的Sequelize或子句

我正在寻找一种方法来编写一个查询，其中包含一个引用多个模型（表）的OR子句

我希望sql最终看起来像这样：

select *
from Department
inner join Office on Department.OfficeId = Office.Id
where Office.Name like 'spokane%'
or Department.Name like 'spokane%'

select *
from Department
inner join Office on Department.OfficeId = Office.Id and Office.name like 'spokane%'
where Department.name like 'spokane%'

我见过关于过滤联接表的类似问题，答案如下所示

options.include = [{
    model: offices.model,
    where: {
        name: {
           $like: 'spokane%'
        }
    }
  }];

options.where = Sequelize.or(
    {
       'name': {
          $like: 'spokane%'
        }
    });

departments.findAndCount(options);

但是，这不会生成正确的sql

它吐出这样的东西：

select *
from Department
inner join Office on Department.OfficeId = Office.Id
where Office.Name like 'spokane%'
or Department.Name like 'spokane%'

select *
from Department
inner join Office on Department.OfficeId = Office.Id and Office.name like 'spokane%'
where Department.name like 'spokane%'

---

任何帮助都将不胜感激。

谢谢！我不得不修改include以使其成为必需的，但后来它工作得很好

{model:offices.model，required:true}

谢谢@JuanitoCROM，

required

选项帮助了我

options.where = {
  $or: [
    sequelize.where(sequelize.col('office.name'), { $like: 'foo'}),
    sequelize.where(sequelize.col('department.name'), { $like: 'foo'})
  ]
}