如何编写自动交互式shell脚本?
我只想写一个shell脚本,在运行命令时自动输入用户名和密码提示, 我试过这个,但没用。请帮我找出路如何编写自动交互式shell脚本?,shell,expect,Shell,Expect,我只想写一个shell脚本,在运行命令时自动输入用户名和密码提示, 我试过这个,但没用。请帮我找出路 #!/bin/bash #!/usr/bin/expect ls -ltr spawn sudo git pull expect "[sudo] password for sandeep:" send "sandeep123\n" expect "Username :" send "sandeep\n" expect "Password :" send "sandeep121\n
#!/bin/bash
#!/usr/bin/expect
ls -ltr
spawn sudo git pull
expect "[sudo] password for sandeep:"
send "sandeep123\n"
expect "Username :"
send "sandeep\n"
expect "Password :"
send "sandeep121\n"
我得到以下输出:
sandeep@K2-Sandeep-08:~$ ./checkout.sh
total 64
./checkout.sh: line 8: spawn: command not found
couldn't read file "Username:": no such file or directory
./checkout.sh: line 16: send: command not found
couldn't read file "Password:": no such file or directory
./checkout.sh: line 20: send: command not found
expect的语法是
expect -c 'spawn sudo git pull; expect assword; send "password\n"; interact'
其中
spawn sudo git pull
是您的命令,expect assword代码>等待出现assword
,当它发出expect
密码时,expect的语法为
expect -c 'spawn sudo git pull; expect assword; send "password\n"; interact'
其中spawn sudo git pull
是您的命令,expect assword
等待assword
出现,当它出现时expect
发送password
您有两个#!行,但您的脚本一次只能由其中一个程序运行。由于大多数命令都是Expect命令,请删除#/bin/bash
行,以便脚本按Expect运行。但是,行ls-ltr
不是Expect命令,将导致错误,但是您可以通过将其转换为put[exec ls-ltr]
来解决此问题。有关详细信息,请参见您有两个!行,但您的脚本一次只能由其中一个程序运行。由于大多数命令都是Expect命令,请删除#/bin/bash
行,以便脚本按Expect运行。但是,行ls-ltr
不是Expect命令,将导致错误,但是您可以通过将其转换为put[exec ls-ltr]
来解决此问题。有关更多详细信息,请参阅