Spring &引用；未识别字段（..），未标记为可忽略“；当jaxb解组xml输入时

在一个典型的SpringMVC项目中，我试图访问从外部webservice源获取的对象。到目前为止，这些数据的实际集成并不是我在项目中的一部分。但它坏了，我得把它修好。也就是说：我并不完全熟悉相关代码

背景 数据 从外部web服务接收的XML数据如下所示：

<offeredServiceTOes>
   <OfferedService deleted="false">
      <id>0001_01-u001/igd</id>
      <title>Umschlagleistung (001)</title>
      <mainType>turnover</mainType>
      <services>
         <service id="tos5yyeivg">
            <title>Umschlag Bahn - Binnenschiff</title>
            <mainType>turnover</mainType>
            <systemId>RailRiver</systemId>
            <meansOfTransport id="motRail">
               <title>Bahn</title>
               <description>Bahn</description>
               <systemId>Rail</systemId>
            </meansOfTransport>
            <meansOfTransportRel id="motRiver">
               <title>Binnenschiff</title>
               <description>Binnenschiff</description>
               <systemId>River</systemId>
            </meansOfTransportRel>
         </service>
         <service id="tos5yyeiw0">
            [...]
         </service>
         [...]
      </services>
      [...]
    </OfferedService>
    [...]
<offeredServiceTOes>

@Override
public List<OfferedServiceTO> getOfferedServices() {
    return restTemplate.getForObject(
            dataServiceUriTemplate, 
            OfferedServiceTOList.class,
            OFFERED_SERVICES
    );

相关的

ServiceTO

类

@XmlRootElement(name="service")
public class ServiceTO
{
    // [...]
    @XmlElement
    public String title;

    /[...]
    @XmlElementWrapper(name="mainServices")
    @XmlElement(name="service")
    public List<ServiceTO> mainServices;
}

问题 问题是，关于xml数据包装，第一个清单的注释，

@xmlementwrapper（name=“services”）@xmlement（name=“service”）

看起来不错。但我一直在犯错误：

[...] nested exception is org.springframework.web.client.ResourceAccessException: I/O error: Unrecognized field "service" (Class a.b.ServiceTO), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@76d697d9; line: 7, column: 18] (through reference chain: a.b.OfferedServiceTO["services"]->a.b.ServiceTO["service"]); nested exception is org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "service" (Class a.b.ServiceTO), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@76d697d9; line: 7, column: 18] (through reference chain: a.b.OfferedServiceTO["services"]->a.b.ServiceTO["service"])
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:328)

通过注释

@xmlementwrapper（name=“services”）

解决了类似的相关问题。但这已经存在

如果有任何建议，我将不胜感激。多谢各位

---

--马丁

好的，这比预期的容易。列表字段需要一个包装层。仔细查看json文档可以发现解决方案：

在OfferedServiceTO.class

@XmlElementWrapper(name="services")
@XmlElement(name="service")
public List<ServiceTO> services;

其中

ServiceTOList.class

必须类似于：

@XmlRootElement(name="service")
public class ServiceTOList extends ArrayList<ServiceTO> {

    public List<ServiceTO> services;
}

@XmlRootElement（name=“service”）
公共类服务列表扩展了ArrayList{
公开名单服务；
}

[...] nested exception is org.springframework.web.client.ResourceAccessException: I/O error: Unrecognized field "service" (Class a.b.ServiceTO), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@76d697d9; line: 7, column: 18] (through reference chain: a.b.OfferedServiceTO["services"]->a.b.ServiceTO["service"]); nested exception is org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "service" (Class a.b.ServiceTO), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@76d697d9; line: 7, column: 18] (through reference chain: a.b.OfferedServiceTO["services"]->a.b.ServiceTO["service"])
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:328)

@XmlElementWrapper(name="services")
@XmlElement(name="service")
public List<ServiceTO> services;

@XmlElement(name="services")
public ServiceTOList services;

@XmlRootElement(name="service")
public class ServiceTOList extends ArrayList<ServiceTO> {

    public List<ServiceTO> services;
}