Sql server 2005 从sql server中的同一个表中检索最小和最大时间

我有一张表，有签到和注销的价值

**id   Date     Time   Status**
  01   1/02/12  8:10   Entry
  01   1/02/12  9:00   Exit
  01   1/02/12  9:10   entry
  01   1/02/12  17:00  Exit
  02   1/02/12  8:10   Entry
  02   1/02/12  9:00   Exit
  02   1/02/12  9:10   entry
  02   1/02/12  17:00  Exit
  **03   1/02/12  17:00  Exit**

我只需要找出每个id的最小和最大时间

预期结果

**id   Date     Entry     Exit  **
  01   1/02/12  8:10      17:00
  02   1/02/12  8:10      17:00

请帮帮我

此代码工作正常，但如果未添加一个条目，则只添加出口 我想展示一下

id   Date     Entry Exit
---- -------- ----- -----
01   01/02/12 08:10 17:00
02   01/02/12 08:10 17:00
**03   01/02/12 Null  17:00**

请帮帮我

---

提前感谢

写一个如下的查询

Select * from MyTable where Time = (Select min(Time) from MyTable) and Status = 'Entry'

及

编辑：

如果您希望对这样的值进行单个查询，可以按如下方式获得

SELECT DISTINCT MyTable.ID, MyTable.Date, MyTable.Time AS Entry, MyTable_2.Time AS
[Exit] FROM MyTable CROSS JOIN MyTable AS MyTable_2 WHERE (MyTable.Time =
(SELECT MIN(Time) AS Expr1 FROM MyTable AS MyTable_1)) AND (MyTable.Status = 'Entry') 
AND (MyTable_2.Time = (SELECT MAX(Time) AS Expr2 FROM MyTable AS MyTable_3)) AND 
(MyTable_2.Status = 'Exit')

---

根据使用的数据类型，类似的操作可能会起作用

declare @T table
(
  id varchar(2),
  [Date] datetime,
  [Time] varchar(5),
  [Status] varchar(5)
)

insert into @T
select '01',   '1/02/12',  '8:10',   'Entry' union all
select '01',   '1/02/12',  '9:00',   'Exit' union all
select '01',   '1/02/12',  '9:10',   'entry' union all
select '01',   '1/02/12',  '17:00',  'Exit' union all
select '02',   '1/02/12',  '8:10',   'Entry' union all
select '02',   '1/02/12',  '9:00',   'Exit' union all
select '02',   '1/02/12',  '9:10',   'entry' union all
select '02',   '1/02/12',  '17:00',  'Exit'

select id,
       convert(varchar(8), [Date], 1) as [Date],
       convert(varchar(5), min([Time]), 108) as [Entry],
       convert(varchar(5), max([Time]), 108) as [Exit]
from
  (
    select id,
           [Date],
           cast([Time] as datetime) as [Time],
           row_number() over(partition by id order by [Date]+cast([Time] as datetime) asc) as rn1,
           row_number() over(partition by id order by [Date]+cast([Time] as datetime) desc) as rn2
    from @T
  ) as T
where T.rn1 = 1 or
      T.rn2 = 1
group by id, [Date]

结果:

id   Date     Entry Exit
---- -------- ----- -----
01   01/02/12 08:10 17:00
02   01/02/12 08:10 17:00

---

您的专栏的数据类型是什么？@kknaufal-很高兴听到。然后你应该考虑把答案作为正确的答案，用左边的复选标记。这将向社区发出信号，表明这个问题已经得到了回答。

id   Date     Entry Exit
---- -------- ----- -----
01   01/02/12 08:10 17:00
02   01/02/12 08:10 17:00