Sql server 2008 获取SQL中的“事件链”

我有一张这样的桌子：

CustomerID | ContactTime     | AttemptResult 
-----------+-----------------+-----------------
1          | 1/1/2016 5:00   | Record Started
1          | 1/1/2016 6:00   | Appointment 
2          | 1/2/2016 5:00   | Record Started
1          | 1/3/2016 6:00   | Sold
2          | 1/2/2016 5:00   | Sold
3          | 1/4/2016 5:00   | Record Started
3          | 1/4/2016 6:00   | Sold

从

我怎样才能以一种方式来查询它，从而按照尝试结果的顺序获取所有组合？比如：

CustID | Sequence
-------+--------------------------------------
1      | Record Started -> Appointment -> Sold 
2      | Record Started ->  Sold 
3      | Record Started ->  Sold 

---

我甚至不知道从哪里开始

如果这是您的完整数据集，我可以帮助您。否则我需要看更多。使用称为窗口函数的东西。下面是对每个CustomerID有多少个条目进行索引或跟踪

    Select *, row_number() over (partition CustomerID group by ContactTime) as Combo
    into #temp
    from table

然后数一数有多少2人的组合发生记录开始->售出，3人的组合发生记录开始->约会->售出

   Select CustomerID, max(Combo) as MaxCombo
   into #temp1
   from #temp
   group by CustomerId

   Select MaxCombo, count(*)
   from #temp1
   group by MaxCombo

您也可以使用公共表表达式代替这些临时表，但我不想添加太多混淆

这给了我“CustomerID”附近不正确的语法。我将其更改为按CustomerID顺序按ContactTime分区，并修复了错误，但结果不是我想要的。

   Select CustomerID, max(Combo) as MaxCombo
   into #temp1
   from #temp
   group by CustomerId

   Select MaxCombo, count(*)
   from #temp1
   group by MaxCombo