Sql server 2008 查询未返回正确的结果--Sql Server Xquery

我的示例Xml如下所示：

<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1">
  <tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff>
</tst:Root>

 -- Set up the XML table to demonstrate
 declare @table table
 (
      ID int,
      xmlDoc  xml
 )

 -- insert your example XML
 insert into @table 
 Values (1, '<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1"><tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff></tst:Root>');

 -- Do the query
 with xmlnamespaces (Default 'http://tempuri.org/some.xsd')
 select ID, xmlDoc.query('//Root/stuff/text()') as SampleXml
 from @table

这是一个返回一切：这是第一。我想展示的是什么

WITH XMLNAMESPACES (Default 'http://tempuri.org/some.xsd')
SELECT     

    a.value('.', 'nvarchar(100)') as SampleXml
    From
    XmlTable As x
    Cross Apply XmlDoc.nodes('Root/stuff') a(a)

如何排除注释节点，但仍能获得正确的结果

编辑：

我想像这样归还：

<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1">
  <tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff>
</tst:Root>

 -- Set up the XML table to demonstrate
 declare @table table
 (
      ID int,
      xmlDoc  xml
 )

 -- insert your example XML
 insert into @table 
 Values (1, '<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1"><tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff></tst:Root>');

 -- Do the query
 with xmlnamespaces (Default 'http://tempuri.org/some.xsd')
 select ID, xmlDoc.query('//Root/stuff/text()') as SampleXml
 from @table

有没有比以下方法更简单的方法：

WITH XMLNAMESPACES (Default 'http://tempuri.org/some.xsd')
SELECT     

a.value('text()[1]', 'nvarchar(100)') + a.value('text()[2]', 'nvarchar(100)') + a.value('text()[3]', 'nvarchar(100)')  as SampleXml

From
XmlTable As x
Cross Apply XmlDoc.nodes('Root/stuff') a(a)

试试这个：

 declare @xml xml;

 set @xml = convert(xml, 'your XML');

 with xmlnamespaces (Default 'http://tempuri.org/some.xsd')
 select @xml.query('//stuff/text()')

假设您有一个包含XML列的表，它将如下所示：

<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1">
  <tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff>
</tst:Root>

 -- Set up the XML table to demonstrate
 declare @table table
 (
      ID int,
      xmlDoc  xml
 )

 -- insert your example XML
 insert into @table 
 Values (1, '<tst:Root xmlns:tst="http://tempuri.org/some.xsd" SchemaVersion="0.2.1234.12345" RevNumber="1"><tst:stuff someID="1">This is <tst:comment>1st.</tst:comment> what I <tst:comment>2nd</tst:comment>just want to show</tst:stuff></tst:Root>');

 -- Do the query
 with xmlnamespaces (Default 'http://tempuri.org/some.xsd')
 select ID, xmlDoc.query('//Root/stuff/text()') as SampleXml
 from @table

这就是我的结果：

---

谢谢你的回复，我希望它是一行而不是3行！我可以通过我发布的最新查询得到它，我只是想知道是否有更好的方法！这似乎不是最好的办法。对良好的反应投了赞成票。再次感谢！它可以比你做的更简单。假设您的XML文档是记录中的一个字段，您根本不需要使用交叉应用，除非您想做其他您没有提到的事情。有关示例，请参见我的更新答案。