Sql server 从列表到网格的SQL结果集

我已经加入了两个数据表

Student 
UPN | Name

及

我编写了以下查询，以显示所有值的列表

SELECT student.upn,
       subject,
       result
FROM   student
       JOIN subject
         ON subject.upn = student.upn

这将导致以下结果

UPN             Subject       Result
8152760         English       3c
8138130         Spanish       2b
8152760         Spanish       3c
8128500         English       3c
8152760         Mathematics   2b
8152760         French        2b

我想做的是让resultset为每个不同的学生显示每个主题的一列，因此如下所示：

UPN             English      French      Mathematics      Spanish
8152760         3c           2b          2b               3c
8138130         NULL         NULL        NULL             2b
8128500         3c           NULL        NULL             NULL

理想情况下，我希望它能根据我的主题名称自动生成列，但如果这更简单，我很乐意硬编码它们。

给你：

declare @t as table (UPN int, Subject varchar(50), Result varchar(3))
insert into @t values(8152760, 'English'     ,  '3c')
insert into @t values(8138130, 'Spanish'     ,  '2b')
insert into @t values(8152760, 'Spanish'     ,  '3c')
insert into @t values(8128500, 'English'     ,  '3c')
insert into @t values(8152760, 'Mathematics' ,  '2b')
insert into @t values(8152760, 'French'      ,  '2b')



select distinct t.upn, 
e.Result as Enlish,
s.Result as Spanish,
f.Result as French,
m.Result as Mathematics
from @t t
left join @t e on e.UPN = t.upn and e.Subject = 'English'
left join @t s on s.UPN = t.upn and s.Subject = 'Spanish'
left join @t f on f.UPN = t.upn and f.Subject = 'French'
left join @t m on m.UPN = t.upn and m.Subject = 'Mathematics'

PIVOT

version仅适用于聚合，这就是我删除注释的原因）

---

@谢谢你的帮助。尽管你的评论到哪里去了？这太棒了@rudym。唯一的问题是我的resultset不限于示例中指定的值。是否可以将insert从特定值更改为列名引用？您可以动态生成执行字符串并执行它。像

Declare@sql1 varchar（max）Declare@sql2 varchar（max）Select@sql1='long string'Select@sql2='long string part 2'exec（@sql1+@sql2）

declare @t as table (UPN int, Subject varchar(50), Result varchar(3))
insert into @t values(8152760, 'English'     ,  '3c')
insert into @t values(8138130, 'Spanish'     ,  '2b')
insert into @t values(8152760, 'Spanish'     ,  '3c')
insert into @t values(8128500, 'English'     ,  '3c')
insert into @t values(8152760, 'Mathematics' ,  '2b')
insert into @t values(8152760, 'French'      ,  '2b')



select distinct t.upn, 
e.Result as Enlish,
s.Result as Spanish,
f.Result as French,
m.Result as Mathematics
from @t t
left join @t e on e.UPN = t.upn and e.Subject = 'English'
left join @t s on s.UPN = t.upn and s.Subject = 'Spanish'
left join @t f on f.UPN = t.upn and f.Subject = 'French'
left join @t m on m.UPN = t.upn and m.Subject = 'Mathematics'

SELECT UPN, 
[English]        ,
[Spanish]        ,                       
[Mathematics]    ,
[French]
FROM
(SELECT UPN, Subject, Result 
    FROM @t) AS SourceTable
PIVOT
(
count(Result)
FOR Subject IN ([English]        ,
                [Spanish]        ,                       
                [Mathematics]    ,
                [French])
) AS PivotTable;