Sql server 将IF..ELSE与multi INSERT一起使用到Using子查询中

我在数据库上有两个表通过外键相互关联 表1是期刊 表2是日志 我有一个查询来检查表journal中当前日期是否有行。如果有记录，它将向journalEntries插入记录 如果为空，则将在日记账表1上插入记录，然后插入日记账表2

我尝试了不同的方法，但不起作用

if (select j_id from journal where [date] > (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) is null
insert into journal values (getdate() as [date], getdate() as [insert_date], '' as notes)
insert into journalentries (j_id, acc_num, credit, debit, [user_id], note)
select (select (select j_id from Journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) as j_id, @acc_num, @credit, @debit, @user_id, @note)

else
insert into journalentries (j_id, acc_num, credit, debit, [user_id], note)
select (select j_id from Journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) as j_id, @acc_num, @credit, @debit, @user_id, @note
end

另一种方式

if(select j_id from journal where [date] in ('2019-01-01')) is null
insert journal([date], insert_date, notes)
OUTPUT inserted.j_id, '2019-01-01', '2019-01-01', ''
INTO dbo.journalentries(j_id, acc_num, credit, debit, [user_id], note)
values (j_id, @acc_num, @credit, @debit, @user_id, @note)
else
select (select j_id from Journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) as j_id, @acc_num, @credit, @debit, @user_id, @note

---

就像一个指针，太长了，不适合评论

    if (select j_id from journal where [date] > (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) is null
    begin 
    insert into journal  select getdate() as [date], getdate() as [insert_date], '' as notes;
    --insert into journalentries j_id, acc_num, credit, debit, [user_id], note); '!! where are you selecting this from?
    select (select (select j_id from Journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) as j_id, @acc_num, @credit, @debit, @user_id, @note);
    end 
    else
    begin
    --insert into journalentries (j_id, acc_num, credit, debit, [user_id], note)  -- !! where are you selecting this from?
    select (select j_id from Journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111))) as j_id, @acc_num, @credit, @debit, @user_id, @note
    end

我使用了scop_identity（），它很有效

declare @j_id int = (select j_id from journal where [date] in (SELECT CONVERT(VARCHAR(10),GETDATE(),111)))
if @j_id is null
    begin 
    insert into journal values (getdate(), getdate(), '') set @j_id = SCOPE_IDENTITY(); insert into journalentries (j_id, acc_num, credit, debit, [user_id], note) values (@j_id, @acc_num, @credit, @debit, @user_id, '');
    end 
    else
    begin
    insert into journalentries (j_id, acc_num, credit, debit, [user_id], note)values (@j_id, @acc_num, @credit, @debit, @user_id, '')
    end

---

什么不起作用？有什么特别的错误信息吗？您是否需要在IF…..中包含块。。。。。其他的使用BEGIN和END？insert语句不起作用，它没有添加记录。它在第一个块中给我一个语法错误。小心，如果第一个查询返回多个结果，我将使用

MAX（j_id）

或

TOP 1 j_id

，以确保安全