Sql server 如何计算中位数？

我需要计算一组数据的中位数，因此我创建了一个临时表，并尝试在线跟踪一些文章，但没有成功，以下是我正在处理的内容：

CREATE TABLE #QuizTemp (QuizProfileID INT,Cnt INT,TotalScore INT)

INSERT INTO #QuizTemp
SELECT QuizAnswers.QuizProfileID, COUNT(QuizAnswers.QuizProfileID) AS Cnt, SUM(QuizAnswers.AnsweredYes) As TotalScore 
FROM         QuizAnswers INNER JOIN
                      Quizzes ON QuizAnswers.QuizID = Quizzes.QuizID
WHERE     (Quizzes.PartnerID = 16) 
GROUP BY QuizAnswers.QuizProfileID
HAVING COUNT(QuizAnswers.QuizProfileID)= 5

SELECT COUNT(*) AS CNT, Avg(TotalScore) AS AvgTotalScore  FROM #QuizTemp

DROP TABLE #QuizTemp

---

平均值很大，现在我需要中间值。< /P> < P>尝试在插入中捕获行计数，然后使用RoWo编号（）：在中间选择行：

编辑

下面是一个没有临时表的解决方案：

DECLARE @YourTable  table (TotalScore int)
INSERT INTO @YourTable Values (1)
INSERT INTO @YourTable Values (2)
INSERT INTO @YourTable Values (3)
INSERT INTO @YourTable Values (40)
INSERT INTO @YourTable Values (50)
INSERT INTO @YourTable Values (60)
INSERT INTO @YourTable Values (70)

;with allrows as
(
    SELECT
        TotalScore, ROW_NUMBER() OVER (ORDER BY TotalScore) AS RowNumber
        FROM @YourTable
)
,MaxRows AS
(SELECT MAX(RowNumber) AS CNT,CONVERT(int,ROUND(MAX(RowNumber)/2.0,0)) AS Middle FROM allrows)
SELECT 
    m.CNT
    ,(SELECT AVG(TotalScore) FROM allrows) AS AvgTotalScore  
    ,a.TotalScore AS Median
    ,m.Middle AS MedianRowNumber
    FROM allrows              a
        CROSS JOIN MaxRows    m
    WHERE a.RowNumber=m.Middle

输出：

CNT                  AvgTotalScore        Median      MedianRowNumber
-------------------- -------------------- ----------- --------------------
7                    32                   40          4

(1 row(s) affected)

如果您将第一个CTE编辑为：

;with allrows as
(
    SELECT QuizAnswers.QuizProfileID, COUNT(QuizAnswers.QuizProfileID) AS Cnt, SUM(QuizAnswers.AnsweredYes) As TotalScore 
    , ROW_NUMBER() OVER (ORDER BY TotalScore) AS RowNumber
    FROM         QuizAnswers INNER JOIN
                          Quizzes ON QuizAnswers.QuizID = Quizzes.QuizID
    WHERE     (Quizzes.PartnerID = 16) 
    GROUP BY QuizAnswers.QuizProfileID
    HAVING COUNT(QuizAnswers.QuizProfileID)= 5
)

---

它应该适用于您的查询

不过，数值的中值通常已经结束。仅使用以下示例：

DECLARE @testTable TABLE 
( 
    VALUE   INT
)
--INSERT INTO @testTable -- Even Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56

--
--INSERT INTO @testTable -- Odd Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 39 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56


DECLARE @RowAsc TABLE
(
    ID      INT IDENTITY,
    Amount  INT
)

INSERT INTO @RowAsc
SELECT  VALUE 
FROM    @testTable 
ORDER BY VALUE ASC

SELECT  AVG(amount)
FROM @RowAsc ra
WHERE ra.id IN
(
    SELECT  ID 
    FROM    @RowAsc
    WHERE   ra.id -
    (
        SELECT  MAX(id) / 2.0 
        FROM    @RowAsc
    ) BETWEEN 0 AND 1

)

DECLARE @testTable TABLE 
( 
    VALUE   INT
)
--INSERT INTO @testTable -- Even Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56

--
--INSERT INTO @testTable -- Odd Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 39 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56


DECLARE @RowAsc TABLE
(
    ID      INT IDENTITY,
    Amount  INT
)

INSERT INTO @RowAsc
SELECT  VALUE 
FROM    @testTable 
ORDER BY VALUE ASC

SELECT  AVG(amount)
FROM @RowAsc ra
WHERE ra.id IN
(
    SELECT  ID 
    FROM    @RowAsc
    WHERE   ra.id -
    (
        SELECT  MAX(id) / 2.0 
        FROM    @RowAsc
    ) BETWEEN 0 AND 1

)