Sql server 上一行和下一行记录
我有以下输出Sql server 上一行和下一行记录,sql-server,sql-server-2012,Sql Server,Sql Server 2012,我有以下输出 ID Number Speed LAT LONG DATETIME 101 AB01 15 73.066016 33.5840768 9/1/15 23:10 101 AB01 20 73.0619712 33.5871456 9/1/15 23:30 101 AB01 0 73.0722176 33.6007488 9/1/
ID Number Speed LAT LONG DATETIME
101 AB01 15 73.066016 33.5840768 9/1/15 23:10
101 AB01 20 73.0619712 33.5871456 9/1/15 23:30
101 AB01 0 73.0722176 33.6007488 9/1/15 23:45
101 AB01 0 73.0722112 33.6007488 9/2/15 02:10
101 AB01 0 73.0722176 33.6007008 9/2/15 02:35
101 AB01 0 73.0722432 33.6007456 9/2/15 04:35
101 AB01 0 73.0721664 33.6007904 9/3/15 12:35
101 AB01 0 73.072192 33.6007488 9/3/15 13:35
101 AB01 0 73.072192 33.6007488 9/4/15 11:35
101 AB01 0 73.072192 33.6007488 9/4/15 14:35
101 AB01 1 73.072192 33.6007488 9/5/15 14:35
但所需的输出是
ID Number Speed LAT LONG DATETIME
101 AB01 15 73.066016 33.5840768 9/1/15 23:10
101 AB01 20 73.0619712 33.5871456 9/1/15 23:30
101 AB01 0 73.0722176 33.6007488 9/1/15 23:45
101 AB01 0 73.072192 33.6007488 9/4/15 14:35
101 AB01 1 73.072192 33.6007488 9/5/15 14:35
我想跳过额外的0速度值。如果包括这些0,则会增加0的查询响应时间。
代码尝试
SELECT Distinct ID,Number,Speed,LAT,LONG,DATETIME
FROM table
group by D,Number,Speed,LAT,LONG,DATETIME
如果这是您真正想要的,您可以使用窗口函数来检测速度不连续性:
SELECT ID, Number, Speed, LAT, [LONG], [DATETIME]
FROM (
SELECT ID, Number, Speed, LAT, [LONG], [DATETIME],
LEAD(Speed) OVER (PARTITION BY ID, Number
ORDER BY [DATETIME]) AS NextSpeed,
LAG(Speed) OVER (PARTITION BY ID, Number
ORDER BY [DATETIME]) AS PrevSpeed
FROM mytable) AS t
WHERE Speed <> COALESCE(NextSpeed, -1) OR Speed <> COALESCE(PrevSpeed, -1)
请包括您的编码尝试。您的问题是什么?你试了什么?您如何识别要筛选和保留的记录?@edwinstoeler Speed 0表示车辆不会更改其位置。因此,我需要位置和最后一站位置。