SQL Server：按组组合值

我有以下数据。我需要在status by ID上添加一个带有最终日期的列。因此，第一行的最终日期将是第二行的日期

原始数据：

ID   | STATUS  |  DATE
-----+---------+-----------
1    | A       | 2020-01-03
1    | B       | 2020-01-07
1    | C       | 2020-01-14
2    | A       | 2020-01-04

预期结果：

ID   | STATUS  | DATE       | FINAL_DATE
-----+---------+------------+------------
1    | A       | 2020-01-03 | 2020-01-07
1    | B       | 2020-01-07 | 2020-01-14
1    | C       | 2020-01-14 |
2    | A       | 2020-01-04 |

如何在SQLServer中实现它？有什么想法吗？

使用窗口功能：

select *,
  lead(date) over(partition by id order by date) FINAL_DATE
from tablename

请参阅。
结果:

---

如果需要向表中添加列，请执行以下操作：

alter table original add column final_date date;

update o
    set final_date = new_final_date
    from (select o.*,
                 lead(date) over (partition by id order by date) as new_final_date
          from original o
         ) o;

---

您想在表中添加一个新列，还是只需要一个select查询？

alter table original add column final_date date;

update o
    set final_date = new_final_date
    from (select o.*,
                 lead(date) over (partition by id order by date) as new_final_date
          from original o
         ) o;