Oracle SQL:查找重复的行

我有下表

itemId   Name   PartNum    Price
 1      apple    123       0.99
 2      orange   234       0.5
 3      apple    123       0.99

我想找到重复的行。它应该输出

ItemId  Name  PartNum  Price
 1     apple    123    0.99
 3     apple    123    0.99

---

如何做？？？？

现在我明白了，你可以这样做：

select * from yourTable where name in (
  select name from (
    SELECT Name, PartNum, Price, count(ItemId) qtd
    FROM yourTable 
    group by Name, PartNum, Price,) 
  where qtd>1)

---

现在我明白了，你可以这样做：

select * from yourTable where name in (
  select name from (
    SELECT Name, PartNum, Price, count(ItemId) qtd
    FROM yourTable 
    group by Name, PartNum, Price,) 
  where qtd>1)

---

有两种方法可以实现这一点，基本上就是将表本身连接起来。下面是一个使用

公共表表达式

和

rank（）

函数的解决方案：

with cte as (
  select itemId, 
    name, 
    partnum, 
    price, 
    rank() over (order by name, partnum, price) rnk
  from yourtable
  ) 
select distinct c.* 
from cte c
  join cte c2 on c.rnk = c2.rnk and c.itemid != c2.itemid

---

以下是另一种方法：

select distinct y.* 
from yourtable y
  join yourtable y2 on 
      y.name = y2.name and 
      y.partnum = y2.partnum and 
      y.price = y2.price and 
      y.itemid != y2.itemid

---

有几种方法可以实现这一点，基本上就是将表本身连接起来。下面是一个使用

公共表表达式

和

rank（）

函数的解决方案：

with cte as (
  select itemId, 
    name, 
    partnum, 
    price, 
    rank() over (order by name, partnum, price) rnk
  from yourtable
  ) 
select distinct c.* 
from cte c
  join cte c2 on c.rnk = c2.rnk and c.itemid != c2.itemid

---

以下是另一种方法：

select distinct y.* 
from yourtable y
  join yourtable y2 on 
      y.name = y2.name and 
      y.partnum = y2.partnum and 
      y.price = y2.price and 
      y.itemid != y2.itemid

---

克劳迪奥的答案非常接近，但要根据重复数过滤结果，您需要添加having子句：

select name, partnum, price
from yourTable 
group by name, partnum, price 
having count(itemId) > 1

---

Claudio的答案非常接近，但要根据重复数过滤结果，您需要添加having子句：

select name, partnum, price
from yourTable 
group by name, partnum, price 
having count(itemId) > 1

---

这是另一种选择

SELECT t1.itemId, t1.name, t1.partNum, t1.price
FROM table1 t1
INNER JOIN (SELECT name, partNum, price, COUNT(*) AS count
            FROM table1
            GROUP BY name, partNum, price
            HAVING COUNT(*) > 1
           ) dt ON t1.name = dt.name and t1.partNum = dt.partNum 
                and t1.price = dt.price
ORDER BY t1.itemId

---

检查它，这是另一种选择

SELECT t1.itemId, t1.name, t1.partNum, t1.price
FROM table1 t1
INNER JOIN (SELECT name, partNum, price, COUNT(*) AS count
            FROM table1
            GROUP BY name, partNum, price
            HAVING COUNT(*) > 1
           ) dt ON t1.name = dt.name and t1.partNum = dt.partNum 
                and t1.price = dt.price
ORDER BY t1.itemId

---

检查一下，这是另一种方法：

查询：

select *
from Table1
where Name||','||PartNum in (
    select Name||','||PartNum
    from Table1
    group by Name, PartNum
    having count(*) > 1)

| ITEMID |  NAME | PARTNUM | PRICE |
|--------|-------|---------|-------|
|      1 | apple |     123 |  0.99 |
|      3 | apple |     123 |  0.99 |

：

select *
from Table1
where Name||','||PartNum in (
    select Name||','||PartNum
    from Table1
    group by Name, PartNum
    having count(*) > 1)

| ITEMID |  NAME | PARTNUM | PRICE |
|--------|-------|---------|-------|
|      1 | apple |     123 |  0.99 |
|      3 | apple |     123 |  0.99 |

---

这是另一种方法：

查询：

select *
from Table1
where Name||','||PartNum in (
    select Name||','||PartNum
    from Table1
    group by Name, PartNum
    having count(*) > 1)

| ITEMID |  NAME | PARTNUM | PRICE |
|--------|-------|---------|-------|
|      1 | apple |     123 |  0.99 |
|      3 | apple |     123 |  0.99 |

：

select *
from Table1
where Name||','||PartNum in (
    select Name||','||PartNum
    from Table1
    group by Name, PartNum
    having count(*) > 1)

| ITEMID |  NAME | PARTNUM | PRICE |
|--------|-------|---------|-------|
|      1 | apple |     123 |  0.99 |
|      3 | apple |     123 |  0.99 |

---

这里有另一种方法。这使用分析函数

count（*）

---

这里有另一种方法。这使用分析函数

count（*）

---

这不包括OP需要的

itemid

列。我认为您需要

将表连接回自身以获得该值。这不包括OP需要的
itemid
列。我认为您需要
将表连接回自身以获得该值。