对SQL Server查询中的多行进行计数

我有一个名为Online_Transaction的表，我想显示所有类型的交易，以及每种类型在特定月份完成、拒绝、等待授权的数量。我有这个问题直到现在，但我得到了重复的结果有什么想法吗

SELECT DISTINCT
    TRANSACTION_TYPE_ID ,
    YEAR(CREATED_ON) AS YEAR ,
    MONTH(CREATED_ON) AS MONTH ,
    ( SELECT
          Count(TRANSACTION_TYPE_ID)
      FROM
          ONLINE_TRANSACTION
      WHERE
          ONLINE_TRANSACTION.STATUS_ID = 'COMPLETED' AND MONTH(CREATED_ON) = '2' ) AS COMPLETED ,
    ( SELECT
          Count(TRANSACTION_TYPE_ID)
      FROM
          ONLINE_TRANSACTION
      WHERE
          ONLINE_TRANSACTION.STATUS_ID = 'DECLINED' AND MONTH(CREATED_ON) = '2' ) AS DECLINED ,
    ( SELECT
          Count(TRANSACTION_TYPE_ID)
      FROM
          ONLINE_TRANSACTION
      WHERE
          ONLINE_TRANSACTION.STATUS_ID = 'FAILED' AND MONTH(CREATED_ON) = '2' ) AS FAILED ,
    ( SELECT
          Count(TRANSACTION_TYPE_ID)
      FROM
          ONLINE_TRANSACTION
      WHERE
          ONLINE_TRANSACTION.STATUS_ID = 'PENDING_AUTH' AND MONTH(CREATED_ON) = '2' ) AS PENDING_AUTH
--(SELECT Count(*) from )
FROM
    ONLINE_TRANSACTION
WHERE
    MONTH(CREATED_ON) = '2'
GROUP BY
    TRANSACTION_TYPE_ID ,
    ONLINE_TRANSACTION.CREATED_ON    

我得到了这些结果：

TRANSACTION_TYPE_ID                  YEAR        MONTH       COMPLETED   DECLINED    FAILED      
------------------------------------ ----------- ----------- ----------- ----------- -------
INSURANCE--TYPE                       2009        2           9712        177         0           
CHEQUEBOOK-TYPE                       2009        2           9712        177         0           
CHEQUE-STOP-YPE                       2009        2           9712        177         0           
PAYMENT-TRANS-TYPE               2009        2           9712        177         0           
DOMESTIC-TRANSFER-TYPE                2009        2           9712        177         0
PAYMENT-TRANS-TYPE                2009        2           9712        177         0           
INTRA-ACCOUNT-TRANS-TYPE              2009        2           9712        177         0           
INTRA-BANK-TRANS-TYPE                 2009        2           9712        177         0           
STANDING-ORDER-TYPE                   2009        2           9712        177         0           
STATEMENT-REORDERING TYPE             2009        2           9712        177         0           
PAYMENTS-TRANS-TYPE             2009        2           9712        177         0           

如您所见，结果是重复的，表中的值应该不同。 有什么想法吗

尝试了以下答案后，我得到了以下结果： 这种类型的结果集-它在不同的行中显示每个交易类型的不同结果，因此，如果说交易类型是内部转账，并且我有10个已完成，2个已拒绝，它将在一行中显示已完成，在另一行中显示已拒绝？如何在每个事务类型的一行中显示它

TRANSACTION_TYPE_ID        YEAR MONTH REJECTED COMPLETED POSTED

ALPHA-INSURANCE-TRANS-TYPE  2009 2       0 12 0 
CHEQUEBOOK-ORDER-TRANS-TYPE 2009 2      0 0 0 
CHEQUEBOOK-ORDER-TRANS-TYPE 2009 2      0 52 0 
CHEQUEBOOK-ORDER-TRANS-TYPE 2009 2      2 0 0 
CHEQUE-STOP-TRANS-TYPE      2009 2      0 3 0
 PAYMENT-TRANS-TYPE         2009 2     0 361 0 
PAYMENT-TRANS-TYPE          2009 2     1 0 0 
DOMESTIC-TRANSFER-TRANS-TYPE 2009 2    0 0 0 
DOMESTIC-TRANSFER-TRANS-TYPE 2009 2   0 541 0 
DOMESTIC-TRANSFER-TRANS-TYPE 2009 2    6 0 0

查询如下所示：

SELECT DISTINCT
    TRANSACTION_TYPE_ID ,
    YEAR(CREATED_ON) AS YEAR ,
    MONTH(CREATED_ON) AS MONTH ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-REJECTED ' THEN 1
          ELSE 0
        END) AS REJECTED ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-COMPLETED ' THEN 1
          ELSE 0
        END) AS COMPLETED ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-DECLINDED ' THEN 1
          ELSE 0
        END) AS DECLINED ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-FAILED' THEN 1
          ELSE 0
        END) AS FAILED ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-PENDING-AUTH ' THEN 1
          ELSE 0
        END) AS PENDING_AUTH ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-PENDING-POST ' THEN 1
          ELSE 0
        END) AS PENDING_POST ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'STATUS-TRANS-PENDING' THEN 1
          ELSE 0
        END) AS PENDING ,
    SUM(CASE ONLINE_TRANSACTION.STATUS_ID
          WHEN 'ALPHA-STATUS-TRANS-POSTED' THEN 1
          ELSE 0
        END) AS POSTED
FROM
    ONLINE_TRANSACTION
WHERE
    MONTH(CREATED_ON) = '2'
GROUP BY
    TRANSACTION_TYPE_ID ,
    YEAR(CREATED_ON) ,
    MONTH(CREATED_ON) ,
    STATUS_ID

---

在子查询中需要另一个WHERE子句来链接事务类型ID

SELECT DISTINCT 
  TRANSACTION_TYPE_ID, YEAR(CREATED_ON)AS YEAR, MONTH(CREATED_ON)AS MONTH ,
(SELECT Count(TRANSACTION_TYPE_ID)  FROM ONLINE_TRANSACTION 
 WHERE ONLINE_TRANSACTION.STATUS_ID ='COMPLETED'AND MONTH(CREATED_ON)='2'
    AND TRANSACTION_TYPE_ID=ot.TRANSACTION_TYPE_ID) AS COMPLETED,
(SELECT Count(TRANSACTION_TYPE_ID) FROM ONLINE_TRANSACTION 
 WHERE ONLINE_TRANSACTION.STATUS_ID ='DECLINED'AND MONTH(CREATED_ON)='2'
    AND TRANSACTION_TYPE_ID=ot.TRANSACTION_TYPE_ID) AS DECLINED,
(SELECT Count(TRANSACTION_TYPE_ID) from ONLINE_TRANSACTION
 WHERE  ONLINE_TRANSACTION.STATUS_ID ='FAILED' AND MONTH(CREATED_ON)='2'
    AND TRANSACTION_TYPE_ID=ot.TRANSACTION_TYPE_ID) AS FAILED,
(SELECT Count(TRANSACTION_TYPE_ID) from ONLINE_TRANSACTION
 WHERE  ONLINE_TRANSACTION.STATUS_ID ='PENDING_AUTH'AND MONTH(CREATED_ON)='2'
    AND TRANSACTION_TYPE_ID=ot.TRANSACTION_TYPE_ID) AS PENDING_AUTH
FROM ONLINE_TRANSACTION ot
WHERE MONTH(CREATED_ON)='2'
GROUP BY TRANSACTION_TYPE_ID,ONLINE_TRANSACTION.CREATED_ON

---

嵌套select语句中的where子句不区分不同的事务类型。数字始终是总金额

试着调查一下总数和情况

TRANSACTION_TYPE_ID, YEAR(CREATED_ON)AS YEAR, MONTH(CREATED_ON)AS MONTH ,
  SUM(CASE ONLINE_TRANSACTION.STATUS_ID WHEN 'COMPLETED' THEN 1 ELSE 0 END) AS COMPLETED,
  SUM(CASE ONLINE_TRANSACTION.STATUS_ID WHEN 'DECLINED' THEN 1 ELSE 0 END) AS DECLINED,
  SUM(CASE ONLINE_TRANSACTION.STATUS_ID WHEN 'FAILED' THEN 1 ELSE 0 END) AS FAILED,
  SUM(CASE ONLINE_TRANSACTION.STATUS_ID WHEN 'PENDING_AUTH' THEN 1 ELSE 0 END) AS PENDING_AUTH
FROM ONLINE_TRANSACTION WHERE MONTH(CREATED_ON)='2'
GROUP BY TRANSACTION_TYPE_ID  

主SELECT子句中的附加选择返回到total ONLINE_TRANSACTION表，因此，他们得到的计数与类型无关，而与总体无关

如果将它们中的每一个都更改为您已经拥有的相同分组上的一个和，那么不需要额外的语法进行状态检查-取1表示相等，取0表示差异，在许多SQL方言中bool到0/1 int的转换是自动的，最坏的情况下，您需要一个IF或CASE…WHEN或CAST，无论您选择何种方言

SELECT TRANSACTION_TYPE_ID, YEAR(CREATED_ON) AS YEAR, MONTH(CREATED_ON) AS MONTH , 
SUM(CASE WHEN STATUS_ID = 'COMPLETED' THEN 1 ELSE 0 END) AS Completed,
SUM(CASE WHEN STATUS_ID = 'DECLINED' THEN 1 ELSE 0 END) AS Declined,
SUM(CASE WHEN STATUS_ID = 'FAILED' THEN 1 ELSE 0 END) AS Failed,
SUM(CASE WHEN STATUS_ID = 'PENDING_AUTH' THEN 1 ELSE 0 END) AS Pending_Auth
FROM ONLINE_TRANSACTION
WHERE MONTH(CREATED_ON) = 2
GROUP BY TRANSACTION_TYPE_ID, YEAR(CREATED_ON), MONTH(CREATED_ON)

看看这是否有道理

我尝试了这个方法，只是为了我自己的启发，我想我会分享结果，以防它对其他人有帮助。数据集很小，但显示了原理

sqlite> SELECT * FROM transactions;
id          type_id      status_id
----------  ----------   ----------
1           insurance    completed
2           insurance    declined
3           cheque-stop  completed
4           cheque-stop  completed

sqlite> SELECT
   ...>     type_id,
   ...>     SUM(status_id == 'completed') AS completed,
   ...>     SUM(status_id == 'declined') AS declined
   ...> FROM transactions
   ...> GROUP BY type_id;
type_id      completed   declined
-----------  ----------  ----------
cheque-stop  2           0
insurance    1           1

---

@亚历克斯：你用什么来设置表格格式？@亚历克斯：这就是我想弄明白的？块引号？问题如上所述，我得到了空结果的重复行。我尝试过这样做，但得到了以下结果：Msg 8117，16级，状态1，第2行操作数数据类型varchar对sum运算符无效。这令人惊讶。尝试删除除1之外的SUM子句，看看是否有效。您对上述SQL仍有问题吗？我很抱歉，当没有结果时，我会重复行，而不是在一行中显示结果。我在上述问题中添加了注释。在运行我给出的上述查询后，您可以发布示例数据和结果的屏幕截图吗？为什么我得到这个错误：操作数数据类型varchar对于sum运算符无效。我想，这可能是mysql语法。OP询问TSQL语法。@Andreas：我的例子来自SQLite3，它是一个不同于Microsoft SQL Server的数据库引擎。如果你看到我下面的答案，我会得到重复的行，结果为零。有什么想法吗？