Sql Amazon红移中的语法错误

我有一个语法错误，一个小时内无法解决：

错误：42601:语法错误位于或接近“）”

我尝试在with闭包中运行select语句，它按预期运行。 我想错误在

选择2198作为客户站点下的某个地方，

我使用MySql逻辑（除了带有闭包的

），所以我的错误可能就源于此。
有人吗？
我将
IF
转换为
CASE
，错误再也没有出现：

with all_comp_prices as 
(
    SELECT distinct 
        m2198.to_product_id AS competitor_product_id,
        h_comp.when_seen,
        h_comp.when_seen / 86400 AS day,
        h_comp.price 
    FROM
        tbl_productmatch_2198 as m2198
        JOIN
        (
        select * from tbl_producthistory_2414 
        union select * from tbl_producthistory_2415
         -- insert union more competitors here
        )
        as h_comp

        ON  h_comp.product_id = m2198.to_product_id 
    WHERE
        h_comp.when_seen >= extract(epoch from (getdate() - INTERVAL '7 DAYS'))
)
select 2198 as customer_site,
TIMESTAMP 'epoch' + lt.day*86400 * INTERVAL '1 second' as date,
sum(CASE WHEN ap.price is null THEN 1 else 0 END) as no_price_competitors_products_count,
from
(
select acp.competitor_product_id, max(acp.when_seen) latest_time, acp.day from
    all_comp_prices as acp
    group by acp.competitor_product_id, acp.day
) as lt -- latest times for each products per day
join 
all_comp_prices as ap -- all prices for all times
on lt.latest_time=ap.when_seen and lt.competitor_product_id=ap.competitor_product_id
group by date

既然可以使用ISO日期或时间戳，为什么还要使用epoch？它使编码和调试变得更加容易。阅读手册也有帮助…我使用亚马逊红移，这里是它的文档：我的错，我没有提到它（编辑了问题）。由于红移是基于Postgresql的，所以语法是完全相同的。
getdate（）
证明了它不完全相同。另外：红移是基于一个非常旧的Postgres版本。
with all_comp_prices as 
(
    SELECT distinct 
        m2198.to_product_id AS competitor_product_id,
        h_comp.when_seen,
        h_comp.when_seen / 86400 AS day,
        h_comp.price 
    FROM
        tbl_productmatch_2198 as m2198
        JOIN
        (
        select * from tbl_producthistory_2414 
        union select * from tbl_producthistory_2415
         -- insert union more competitors here
        )
        as h_comp

        ON  h_comp.product_id = m2198.to_product_id 
    WHERE
        h_comp.when_seen >= extract(epoch from (getdate() - INTERVAL '7 DAYS'))
)
select 2198 as customer_site,
TIMESTAMP 'epoch' + lt.day*86400 * INTERVAL '1 second' as date,
sum(CASE WHEN ap.price is null THEN 1 else 0 END) as no_price_competitors_products_count,
from
(
select acp.competitor_product_id, max(acp.when_seen) latest_time, acp.day from
    all_comp_prices as acp
    group by acp.competitor_product_id, acp.day
) as lt -- latest times for each products per day
join 
all_comp_prices as ap -- all prices for all times
on lt.latest_time=ap.when_seen and lt.competitor_product_id=ap.competitor_product_id
group by date