Sql 如何获取最大版本记录？

我有一张如下表：

------------------------------------
Id   FId   UId   Version
1    1     1     1
2    1     2     1
3    1     3     1
4    1     2     2
5    1     3     2
6    1     3     2
7    1     4     2
8    2     1     1
9    2     2     1

那么我希望结果是：

--------------------------
FId  UId   Version
1    2     2
1    3     2
1    4     2
2    1     1
2    2     1

---

如何基于每个FId UId对的最大“版本”编写查询？

这将适用于SQL 2005及更高版本：

select FId, UId, Version 
from MyTable
join (select Fid, Max(Version) as MaxVersion group by Fid) x 
on x.FId = MyTable.FId and x.MaxVersion = MyTable.Version

DECLARE @t TABLE
(Id INT,
Fid INT,
[uid] INT,
[VERSION] INT
)

INSERT @t
SELECT 1,1,1,1
UNION ALL SELECT 2,1,2,1
UNION ALL SELECT 3,1,3,1
UNION ALL SELECT 4,1,2,2
UNION ALL SELECT 5,1,3,2
UNION ALL SELECT 6,1,3,2
UNION ALL SELECT 7,1,4,2
UNION ALL SELECT 8,2,1,1
UNION ALL SELECT 9,2,2,1

;WITH myCTE
AS
(
    SELECT *,
           RANK() OVER (PARTITION BY Fid
                        ORDER BY [VERSION] DESC
                       ) AS rnk
    FROM @t
)
SELECT DISTINCT Fid, [uid],[VERSION]
FROM myCTE
WHERE rnk = 1
ORDER BY Fid, [uid]

---

这将适用于SQL 2005及更高版本：

DECLARE @t TABLE
(Id INT,
Fid INT,
[uid] INT,
[VERSION] INT
)

INSERT @t
SELECT 1,1,1,1
UNION ALL SELECT 2,1,2,1
UNION ALL SELECT 3,1,3,1
UNION ALL SELECT 4,1,2,2
UNION ALL SELECT 5,1,3,2
UNION ALL SELECT 6,1,3,2
UNION ALL SELECT 7,1,4,2
UNION ALL SELECT 8,2,1,1
UNION ALL SELECT 9,2,2,1

;WITH myCTE
AS
(
    SELECT *,
           RANK() OVER (PARTITION BY Fid
                        ORDER BY [VERSION] DESC
                       ) AS rnk
    FROM @t
)
SELECT DISTINCT Fid, [uid],[VERSION]
FROM myCTE
WHERE rnk = 1
ORDER BY Fid, [uid]

---

下面给出了请求的输出

select distinct t2.FId, t2.UId, t2.Version
from
(
    select FId, max(Version) as "Version"
    from MyTable
    group by FId
) t1
inner join MyTable t2 on (t1.FId = t2.FId and t1.Version = t2.Version)
order by t2.FId, t2.UId

---

下面给出了请求的输出

select distinct t2.FId, t2.UId, t2.Version
from
(
    select FId, max(Version) as "Version"
    from MyTable
    group by FId
) t1
inner join MyTable t2 on (t1.FId = t2.FId and t1.Version = t2.Version)
order by t2.FId, t2.UId

---

您显示的结果是否正确-1,3,2应出现两次。如果只需要一次，请使用“选择不同”

foll查询正在运行

with t as(
select 1 as id,   1 as fid  ,  1  as uid,   1 as version union all
select 2 ,   1 ,    2 ,    1  union all
select 3 ,   1  ,   3 ,    1  union all
select 4 ,   1 ,    2   ,  2  union all
select 5  ,  1  ,   3  ,   2  union all
select 6 ,   1  ,   3  ,  2  union all
select 7 ,   1 ,    4  ,   2  union all
select 8  ,  2  ,   1  ,   1  union all
select 9 ,   2  ,   2  ,   1)

select distinct t.fid,t.uid,t.version from t 
inner join(
select fid,max(version) as maxversion from t
group by fid)as grp
on t.fid=grp.fid 
and t.version=grp.maxversion

---

您显示的结果是否正确-1,3,2应出现两次。如果只需要一次，请使用“选择不同”

foll查询正在运行

with t as(
select 1 as id,   1 as fid  ,  1  as uid,   1 as version union all
select 2 ,   1 ,    2 ,    1  union all
select 3 ,   1  ,   3 ,    1  union all
select 4 ,   1 ,    2   ,  2  union all
select 5  ,  1  ,   3  ,   2  union all
select 6 ,   1  ,   3  ,  2  union all
select 7 ,   1 ,    4  ,   2  union all
select 8  ,  2  ,   1  ,   1  union all
select 9 ,   2  ,   2  ,   1)

select distinct t.fid,t.uid,t.version from t 
inner join(
select fid,max(version) as maxversion from t
group by fid)as grp
on t.fid=grp.fid 
and t.version=grp.maxversion

---

为什么

FId=1的行不存在；UID=1；输出中的Version=1

，为什么没有一行表示

FId=1；UID=1；输出中的版本=1

？？