对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE

对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE,sql,database,join,Sql,Database,Join,对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE A References 01 02 04 TABLE B References 01 22 TABLE C References 02 04 22 select COALESCE(a.Value,b.Value) FROM

对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用
HAVING COUNT(*)=1
kludge(正如昨天告诉我的,mysql没有完全连接)
TABLE A References
01
02
04

TABLE B References
01
22
TABLE C References
02
04
22
select
    COALESCE(a.Value,b.Value)
FROM
    a
        full outer join
    b
        on
           a.Value = b.Value
WHERE
    a.Value is null or
    b.Value is null
  SELECT COL1 FROM
    (
      SELECT Col1 FROM TABLE_A
      UNION ALL
      SELECT COL1 FROM TABLE_B
    ) X
     GROUP BY COL1
     HAVING COUNT(*) =1
(  select 'A' as source, reference
   from tableA
   EXCEPT
   select 'A' as source, reference
   from tableB)
UNION ALL
(  select 'B' as source, reference
   from tableB
   EXCEPT
   select 'B' as source, reference
   from tableA)


==================
source | reference
==================
 A       02
 A       04 
 B       22
Select Distinct ( isnull(A.References,B.Referecces))   
from A full join B on A.References<>B.References  
where ( not exists ( Select * from B as B1 where B1.References=A.References )  and A.References is not null )  or  
( not exists ( Select * from A as a1  where a1.References=B.References )  and B.References is not null )
select a.*
FROM
    tblA a LEFT JOIN tblB b on a.ColRef=b.ColRef
where b.ColRef IS NULL
UNION ALL
select b.*
FROM
    tblB b LEFT JOIN tblA a on b.ColRef=a.ColRef
where a.ColRef IS NULL
select * from(
    select * from tblA
    union
    select * from tblB
)x where x.ColRef NOT IN (select a.ColRef From tblA a JOIN tblB b on a.ColRef=b.ColRef)
WITH two AS (
        SELECT val AS val, 'A' AS flag FROM lutser_a
        UNION ALL
        SELECT val AS val, 'B' AS flag FROM lutser_b
        )
SELECT *
FROM two t
WHERE NOT EXISTS (
        SELECT * FROM two nx
        WHERE nx.val = t.val
        AND nx.flag <> t.flag
        );
SELECT ISNULL(TABLE_A.Col1,TABLE_B.Col1) 
FROM TABLE_A
LEFT JOIN TABLE_B ON TABLE_A.Col1 = TABLE_B.Col1 
WHERE TABLE_A.Col1<> TABLE_B.Col1