对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE
对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE,sql,database,join,Sql,Database,Join,对于接触mysql的人来说,kludge可能更受欢迎(正如我昨天被告知的那样,mysql没有完全连接),这就是典型的答案。接触mysql的人可能更喜欢使用HAVING COUNT(*)=1kludge(正如昨天告诉我的,mysql没有完全连接) TABLE A References 01 02 04 TABLE B References 01 22 TABLE C References 02 04 22 select COALESCE(a.Value,b.Value) FROM
HAVING COUNT(*)=1
kludge(正如昨天告诉我的,mysql没有完全连接)
TABLE A References
01
02
04
TABLE B References
01
22
TABLE C References
02
04
22
select
COALESCE(a.Value,b.Value)
FROM
a
full outer join
b
on
a.Value = b.Value
WHERE
a.Value is null or
b.Value is null
SELECT COL1 FROM
(
SELECT Col1 FROM TABLE_A
UNION ALL
SELECT COL1 FROM TABLE_B
) X
GROUP BY COL1
HAVING COUNT(*) =1
( select 'A' as source, reference
from tableA
EXCEPT
select 'A' as source, reference
from tableB)
UNION ALL
( select 'B' as source, reference
from tableB
EXCEPT
select 'B' as source, reference
from tableA)
==================
source | reference
==================
A 02
A 04
B 22
Select Distinct ( isnull(A.References,B.Referecces))
from A full join B on A.References<>B.References
where ( not exists ( Select * from B as B1 where B1.References=A.References ) and A.References is not null ) or
( not exists ( Select * from A as a1 where a1.References=B.References ) and B.References is not null )
select a.*
FROM
tblA a LEFT JOIN tblB b on a.ColRef=b.ColRef
where b.ColRef IS NULL
UNION ALL
select b.*
FROM
tblB b LEFT JOIN tblA a on b.ColRef=a.ColRef
where a.ColRef IS NULL
select * from(
select * from tblA
union
select * from tblB
)x where x.ColRef NOT IN (select a.ColRef From tblA a JOIN tblB b on a.ColRef=b.ColRef)
WITH two AS (
SELECT val AS val, 'A' AS flag FROM lutser_a
UNION ALL
SELECT val AS val, 'B' AS flag FROM lutser_b
)
SELECT *
FROM two t
WHERE NOT EXISTS (
SELECT * FROM two nx
WHERE nx.val = t.val
AND nx.flag <> t.flag
);
SELECT ISNULL(TABLE_A.Col1,TABLE_B.Col1)
FROM TABLE_A
LEFT JOIN TABLE_B ON TABLE_A.Col1 = TABLE_B.Col1
WHERE TABLE_A.Col1<> TABLE_B.Col1