SQL Server中的分组查询帮助

我试图按特定人群对我的数据进行排序。我的数据如下所示：

Origional_Date  ID      FORM    Total
2012-03-01      1855    3       1283
2012-03-01      2869    4       2306
2012-03-01      5555    4       6440
2012-03-01      5555    3       8373
2012-03-01      2527    3       8476
2012-03-01      922     3       823
2012-03-15      2907    4       1420
2012-03-15      5555    3       2892
2012-03-15      2914    4       5008
2012-03-15      2375    3       4594

到目前为止，我的问题是：

DECLARE @StartDate smalldatetime, @EndDate smalldatetime, @Web_ID as smallint
    SET @StartDate = '20120301'
    SET @EndDate = '20120331'
    SET @Web_ID = '5555'

SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, [Origional_Date]), -1) as [Origional_Date]
  ,[ID]
  ,[Form]
  ,SUM([Total]) as [Total]
  FROM mytable
  WHERE [Origional_Date] between @StartDate and @EndDate
    AND [ID] = @Web_ID
  GROUP BY DATEADD(WEEK, DATEDIFF(WEEK, 0, [Origional_Date]), -1), [ID], [Form]
  ORDER BY [Origional_Date], [Form] ASC

我要做的是显示我的数据，如下所示：

Origional_Date  ID      FORM    Total
2012-03-01      Web     3       8373
2012-03-01      Direct  3       10582
2012-03-01      Web     4       6440
2012-03-01      Direct  4       2306
2012-03-15      WEB     3       2892
2012-03-15      Direct  3       4594
2012-03-15      Direct  4       6428

其中Web是ID5555，Direct是其他任何内容

我只是不知道如何使用“if”语句来实现，或者是否需要在“groupby”中实现

---

谢谢大家!

您可以使用case语句来实现这一点

像

用例小句

select case active
    when 1 then 'Active'
    when 0 then 'Inactive'
    end         
from contract

您的情况与此类似：

select case [ID]
    when 5555 then 'Web'
    else 'Direct'
    end as [ID]
from mytable

---

您的ID筛选器每次选择仅返回一个ID。对吗？

select case [ID]
    when 5555 then 'Web'
    else 'Direct'
    end as [ID]
from mytable