Sql 基于值和条件的Oracle XMLTYPE提取
我有一个XML查询示例,如下所示:Sql 基于值和条件的Oracle XMLTYPE提取,sql,xml,oracle,oracle12c,xmltype,Sql,Xml,Oracle,Oracle12c,Xmltype,我有一个XML查询示例,如下所示: SELECT * FROM v$version; Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production PL/SQL Release 12.1.0.2.0 - Production "CORE 12.1.0.2.0 Production" TNS for Linux: Version 12.1.0.2.0 - Production NL
SELECT * FROM v$version;
Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production
PL/SQL Release 12.1.0.2.0 - Production
"CORE 12.1.0.2.0 Production"
TNS for Linux: Version 12.1.0.2.0 - Production
NLSRTL Version 12.1.0.2.0 - Production
XML应该有带STUDENT->DIVISION的S_DAYS节点,我们从XML中获取金额值
有可选节点S_天,其中S_天的PCODE=Child1或PCODE=Child2
当存在Child1或Child2的节点PCODE时,我们必须应用现有行本身
实际结果:
预期结果:
任何帮助都将不胜感激。
谢谢。您可以走回学生s_days节点的兄弟节点: 或者,如果您始终希望在没有学生节点的情况下查看子节点,也可以从第一个XMLTable中获取子节点:
select h.PlanCodeCode, b.amount, b.pcode, b.child1_amount, b.child2_amount
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode'
) h
left join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
, child1_amount number path './../../../S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount'
, child2_amount number path './../../../S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) b on 1=1;
顺便说一句,当您在12c上时,您可以使用交叉应用和外部应用-后者而不是在1=1条件下使用dummy进行外部连接
select h.PlanCodeCode, b.amount, b.pcode, h.child1_amount, h.child2_amount
from t
cross join
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode',
child1_amount number path './PlanCode/S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount',
child2_amount number path './PlanCode/S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) h
left join xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
) b on 1=1;
其中任何一项都会得到与您的样本数据相同的结果:
select h.PlanCodeCode, b.amount, b.pcode, h.child1_amount, h.child2_amount
from t
cross apply
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode',
child1_amount number path './PlanCode/S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount',
child2_amount number path './PlanCode/S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) h
outer apply xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
) b;
您保存了我完整的一天。是否可以有多个条件来获取最终值:例如:如果节点是-->child1_amount number path./PlanCode/S_DAYS[@PCODE=child1]和/PlanCode/S_DAYS[@MYFLAG=YES]/AdditonalFare/additonalfaeamount/@amount'.@ajmalmhd04-是的,您只需要额外的括号。中间位应为S_天[@PCODE=Child2和@MYFLAG=YES]。非常感谢!!!不知道这有什么问题。尽管您可以测试子金额是否都为空。无论如何,如果你有新问题,你需要问一个新问题。
select h.PlanCodeCode, b.amount, b.pcode, h.child1_amount, h.child2_amount
from t
cross apply
xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'/SSO_XML'
passing t.xml
columns PlanCodeCode varchar2(100) path './PlanCode/@PlanCodeCode',
attributes xmltype path './PlanCode',
child1_amount number path './PlanCode/S_DAYS[@PCODE="Child1"]/AdditonalFare/AdditonalFareAmount/@Amount',
child2_amount number path './PlanCode/S_DAYS[@PCODE="Child2"]/AdditonalFare/AdditonalFareAmount/@Amount'
) h
outer apply xmltable(xmlnamespaces(default 'http://www.w3.org/2001/XMLSchema'),
'PlanCode/S_DAYS/STUDENT/DIVISION'
passing h.attributes
columns node_level for ordinality
, amount number path '@Amount'
, pcode varchar2(10) path './../../@PCODE'
) b;
PLANCODECODE | AMOUNT | PCODE | CHILD1_AMOUNT | CHILD2_AMOUNT
:----------- | -----: | :---- | ------------: | ------------:
CHOICE | 150.05 | P123 | 100 | 130
CHOICE | 250.05 | P123 | 100 | 130
CHOICE | 150.05 | P1234 | 100 | 130
CHOICE | 250.05 | P1234 | 100 | 130