SQL获取日期范围内同一表中不同记录的若干项的总和(ORACLE)
我有一个模式如下。我想运行以下查询: 从可以指定的日期范围内获取所有资产、描述、总成本(来自资产表)、驱动因素、polclass、manager(来自资产规格)和(所有增量的总和)作为使用。例如,这里我们可以指定从2015年11月2日到2016年1月30日,我们应该得到增量的总和作为使用量,因此记录如下所示SQL获取日期范围内同一表中不同记录的若干项的总和(ORACLE),sql,oracle,Sql,Oracle,我有一个模式如下。我想运行以下查询: 从可以指定的日期范围内获取所有资产、描述、总成本(来自资产表)、驱动因素、polclass、manager(来自资产规格)和(所有增量的总和)作为使用。例如,这里我们可以指定从2015年11月2日到2016年1月30日,我们应该得到增量的总和作为使用量,因此记录如下所示 ASSETNUM|LOCATION|DESCRIPTION|TOTALCOST|DRIVER|POLCLASS|MANAGER|USAGE -------------------------
ASSETNUM|LOCATION|DESCRIPTION|TOTALCOST|DRIVER|POLCLASS|MANAGER|USAGE
----------------------------------------------------------------------
12345 | HERE | SEDAN |30000 |JOHN | SPORT | JOE | 828(300+78+450)
99999 | . | .........................................
ASSET:
ASSETNUM | LOCATION | DESCRIPTION | TOTALCOST
---------------------------------------------
12345 | HERE | SEDAN |30000
99999 | THERE | SUV |50000
. | . |. |.
ASSETSPEC:
ASSETNUM | ASSETATTRID | ALNVALUE
---------------------------------
12345 | DRIVER | JOHN
12345 | POLCALSS | SPORT
12345 | MANAGER | JOE
99999 | DRIVER | Greg
99999 | POLCLASS | SPORT
99999 | . | .
METERREADING:
ASSETNUM | DELTA | Reading Date
---------------------------------
12345 | 78 | 1/30/2016
12345 | 450 | 12/9/2015
12345 | 300 | 11/2/2015
我想一次又一次地加入表以获取驱动程序、管理器和polclass,但我不知道如何获取日期范围内的增量之和。我的查询是这样的
SELECT V.ASSETNUM,
drivers.ALNVALUE AS Driver,
manager.ALNVALUE AS Manager,
V.DESCRIPTION AS ASSET_DESC,
V.LOCATION,
MAXIMO.LOCATIONS.DESCRIPTION AS Location_description,
V.TOTALCOST,
polclass.ALNVALUE AS POLICY_CLASS,
FROM MAXIMO.ASSET V
INNER JOIN MAXIMO.ASSETSPEC drivers
ON V.ASSETNUM = drivers.ASSETNUM
AND drivers.ASSETATTRID = 'DRIVER'
INNER JOIN MAXIMO.ASSETSPEC polclass
ON V.ASSETNUM = polclass.ASSETNUM
AND polclass.ASSETATTRID = 'POLCLASS'
INNER JOIN MAXIMO.ASSETSPEC manager
ON V.ASSETNUM = manager.ASSETNUM
AND manager.ASSETATTRID = 'MANAGER'
INNER JOIN MAXIMO.LOCATIONS
ON MAXIMO.LOCATIONS.LOCATION = V.LOCATION
INNER JOIN MAXIMO.METERREADING
ON MAXIMO.METERREADING.ASSETNUM = V.ASSETNUM
试试这个:
select assetnum,location,
description,totalcost,
manager,polcalss,driver,
sum(delta) total_delta from
(select * from (
select a.assetnum,
a.location,
a.description,
a.totalcost,
b.assetattrid,
b.alnvalue,
m.delta
from asset a inner join assetspec b on a.assetnum = b.assetnum
inner join meterreading m on a.assetnum = m.assetnum
where m.reading_date between
to_date('1/30/2015','mm/dd/yyyy')
and to_date('1/30/2016','mm/dd/yyyy')
)
pivot
(max(alnvalue) for
(assetattrid) in ('manager' as manager,
'polcalss' as polcalss,
'driver' as driver))
)
group by assetnum,location,description,
totalcost,manager,polcalss,driver;
您可以
PIVOT
assetspec表以每个assetnum列的形式填充数据,而不必三次加入表fwiw。您将需要一个SUM()
aggregate查询来获得您所追求的总数。@Boneist谢谢。请提供您所引用的sql代码给我好吗?您可以找到一些有用的信息,您能解释一下为什么我们必须在那里使用max函数吗?谢谢。@jax仔细想想。对于给定的assetnum
,manager可以有许多行,但输出中只有一个manager列。Pivot查询需要聚合函数根据这些行选择值。它可以是COUNT
,SUM
等。