Sql 循环直到父值为空
我有两张桌子,Sql 循环直到父值为空,sql,oracle,oracle10g,Sql,Oracle,Oracle10g,我有两张桌子,tbl\u文件夹: FOLDER_ID FOLDER_NAME PARENT_FOLDER_ID 1 Folder1 2 Folder1.1 1 3 Folder1.2 1 4 Folder1.1.1 2 5 Folder1.1.2 2 6 Folder1.2.1 3 7 Folde
tbl\u文件夹
:
FOLDER_ID FOLDER_NAME PARENT_FOLDER_ID
1 Folder1
2 Folder1.1 1
3 Folder1.2 1
4 Folder1.1.1 2
5 Folder1.1.2 2
6 Folder1.2.1 3
7 Folder1.2.2 3
和tbl_文件
:
FILE_ID FILE_NAME PARENT_FOLDER_ID ACTIVITY_ID
1 Abc.txt 5 2
2 PQR.txt 2 1
3 XYZ.txt 7 2
我正在将activity\u id
作为输入传递给一个过程,从中我可以获得该activity id的所有文件的parent\u folder\u id
。我想使用tbl\u folder
中的数据获取父文件夹的完整路径
例如,如果我将2作为activity\u id
传递,那么我将获得两个文件:
Abc.txt
-文件的父文件夹ID为5XYZ.txt
-文件的父文件夹ID为7parent\u folder\u id
中,我将获得文件夹的名称,例如Folder1.1.2
。
我将选择该文件夹的parent\u folder\u id
,并获取其名称和父文件夹,依此类推。最后,我将为Abc.txt
生成路径,作为Folder1\Folder1.1\Folder1.1.2
正确的方法是什么?我应该使用循环吗?还是临时桌子?或者其他什么?您可以使用获取每个文件夹的完整路径:
select folder_id, sys_connect_by_path(folder_name, '/') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id;
FOLDER_ID PATH
---------- ----------------------------------------
1 /Folder1
2 /Folder1/Folder1.1
4 /Folder1/Folder1.1/Folder1.1.1
5 /Folder1/Folder1.1/Folder1.1.2
3 /Folder1/Folder1.2
6 /Folder1/Folder1.2/Folder1.2.1
7 /Folder1/Folder1.2/Folder1.2.2
在这里,我们正在为您构建完整的路径
您可以将tbl_文件
加入到该文件中,以获得每个文件的完整路径:
select f.file_name, h.path
from tbl_file f
join (
select folder_id, sys_connect_by_path(folder_name, '/') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id
) h
on h.folder_id = f.parent_folder_id
where f.activity_id = 2;
FILE_NAME PATH
---------- ----------------------------------------
Abc.txt /Folder1/Folder1.1/Folder1.1.2
XYZ.txt /Folder1/Folder1.2/Folder1.2.2
或者使用反斜杠且根文件夹上没有前导斜杠(可以使用ltrim()
删除),这更接近问题中的示例:
select f.file_name, ltrim(h.path, '\') as path
from tbl_file f
join (
select folder_id, sys_connect_by_path(folder_name, '\') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id
) h
on h.folder_id = f.parent_folder_id
where f.activity_id = 2;
FILE_NAME PATH
---------- ----------------------------------------
Abc.txt Folder1\Folder1.1\Folder1.1.2
XYZ.txt Folder1\Folder1.2\Folder1.2.2
在Oracle的更高版本中,您也可以使用递归子查询分解,但在10g中不可用。您可以使用获取每个文件夹的完整路径:
select folder_id, sys_connect_by_path(folder_name, '/') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id;
FOLDER_ID PATH
---------- ----------------------------------------
1 /Folder1
2 /Folder1/Folder1.1
4 /Folder1/Folder1.1/Folder1.1.1
5 /Folder1/Folder1.1/Folder1.1.2
3 /Folder1/Folder1.2
6 /Folder1/Folder1.2/Folder1.2.1
7 /Folder1/Folder1.2/Folder1.2.2
在这里,我们正在为您构建完整的路径
您可以将tbl_文件
加入到该文件中,以获得每个文件的完整路径:
select f.file_name, h.path
from tbl_file f
join (
select folder_id, sys_connect_by_path(folder_name, '/') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id
) h
on h.folder_id = f.parent_folder_id
where f.activity_id = 2;
FILE_NAME PATH
---------- ----------------------------------------
Abc.txt /Folder1/Folder1.1/Folder1.1.2
XYZ.txt /Folder1/Folder1.2/Folder1.2.2
或者使用反斜杠且根文件夹上没有前导斜杠(可以使用ltrim()
删除),这更接近问题中的示例:
select f.file_name, ltrim(h.path, '\') as path
from tbl_file f
join (
select folder_id, sys_connect_by_path(folder_name, '\') as path
from tbl_folder
start with parent_folder_id is null
connect by parent_folder_id = prior folder_id
) h
on h.folder_id = f.parent_folder_id
where f.activity_id = 2;
FILE_NAME PATH
---------- ----------------------------------------
Abc.txt Folder1\Folder1.1\Folder1.1.2
XYZ.txt Folder1\Folder1.2\Folder1.2.2
在更高版本的Oracle中,还可以使用递归子查询分解,但在10g中不可用