如何在sql中求和实现合计

我有一个销售id列表，后面是他们的总销售额和购买量。我现在要计算总销售额和总购买量。我已尝试将totalbuy和totalsell之和插入为总计。但这并没有奏效

select sales_id, 
   SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy, 
   SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell 
from car_orders 
where sales_id like '%%' 
GROUP BY sales_id

或者如果一方只能是“买入”或“卖出”

SELECT 
  sales_id, 
  SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy, 
  SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell,
  COUNT(*) as total
FROM car_orders 
WHERE sales_id like '%%' 
GROUP BY sales_id

---

假设side=buy或sell。

如果需要与

where

子句匹配的所有SalesID的总数，则删除

分组依据

：

select 
   SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy, 
   SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell 
from car_orders 
where sales_id like '%%' 

---

谢谢拉斐尔！它说我必须等待几分钟才能标记为答案。有没有办法将销售id限制为10人，然后根据总数对他们进行排名，目前大约有20个id？@userH是的，但在不同的dbms中解决方案不同，所以。。。您的SQL标记不足；）那么，你能提供一个例子或一个我可以查看的网站来获取信息吗？我刚刚意识到我可能会回显表并使用表排序器（Jquery）进行排序

select sales_id, 
   SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy, 
   SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell,
   SUM(1) as totalbuyplussell 
from car_orders 
where sales_id like '%%' 
GROUP BY sales_id

select 
   SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy, 
   SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell 
from car_orders 
where sales_id like '%%'