树表菜单的SQL查询

我有一个树状结构的表：

ID    Title           ParentID     Orderby 
----------------------------------------
1     All             0            2
2     Banking         1            5
3     USAA Checking   0            0
4     USAA Mastercard 1            9
5     Medical         3            0
6     Jobs            3            100
7     Archive         0            1
8     Active          7            0  
9     BoA Amex        1            1

我需要编写一个SQL查询来生成如下结果（按列排序）：

---

谁能帮我写一个SQL查询？谢谢

您可以使用

row\u number（）


select Id,title, concat(val,'.',case when 
row_number() over(partition by val order by Id)-1=0 then null else 
row_number() over(partition by val order by Id)-1 end) as path,
orderby
from
(
select *,case when parentid=0 then id else parentid end as val
from Categories
)A

如果您有一个层次结构级别，可以尝试下面的查询

 Select  
      C.ID as ID, 
      C.Title  as Title, 
      Case 
        when C.ParentID =0 then cast(C.ID as  varchar(2)) 
        else cast(C.ParentID as varchar(2)) + '.' + cast(C.Order as varchar(3)) 
      END as Path, 
      C.Order 
  from Categories as C

如果有多级层次结构，则需要创建临时表。您需要更新订单，以便我们对所需的输出进行更简单的查询

谢谢
我们可以使用递归CTE进行此操作：

WITH children AS (
    SELECT NULL AS ParentID, ID, Title, Orderby,
        CAST(ID AS VARCHAR(500)) AS Path
    FROM Categories
    WHERE ParentID = 0

    UNION ALL

    SELECT 
       d.ParentID, t.counter + 1, d.ID, d.Title, d.Orderby,
       CAST(CAST(t.Path AS VARCHAR(50)) + '.' +
       CAST(ROW_NUMBER() OVER (PARTITION BY d.ParentID ORDER BY d.ID) AS VARCHAR(50)) AS VARCHAR(500))
    FROM children t
    INNER JOIN Categories AS d
        ON d.ParentID = t.ID
)

SELECT ID, Title, Path, Orderby
FROM children;



请注意，对于给定的父版本，您从未提供用于确定次要版本号的固定逻辑。也就是说，不清楚为什么
Medical
出现在层次结构中早于
Jobs
。
您应该解释您的逻辑考虑使用其他方法，您需要一个递归CTEE解释您如何计算
USAA万事达卡的路径
否，我不理解您的评论。请再次检查，我只是调整了一下问题，让它更容易理解，对不起，因为我的英语不太好
WITH children AS (
    SELECT NULL AS ParentID, ID, Title, Orderby,
        CAST(ID AS VARCHAR(500)) AS Path
    FROM Categories
    WHERE ParentID = 0

    UNION ALL

    SELECT 
       d.ParentID, t.counter + 1, d.ID, d.Title, d.Orderby,
       CAST(CAST(t.Path AS VARCHAR(50)) + '.' +
       CAST(ROW_NUMBER() OVER (PARTITION BY d.ParentID ORDER BY d.ID) AS VARCHAR(50)) AS VARCHAR(500))
    FROM children t
    INNER JOIN Categories AS d
        ON d.ParentID = t.ID
)

SELECT ID, Title, Path, Orderby
FROM children;