如何使用TSQL获取一年中的最后一个星期日?
我需要检查给定的一天是否是任何一年的最后一个星期日,如果是,只使用TSQL返回1如何使用TSQL获取一年中的最后一个星期日?,sql,sql-server,database,tsql,Sql,Sql Server,Database,Tsql,我需要检查给定的一天是否是任何一年的最后一个星期日,如果是,只使用TSQL返回1 我对TSQL不太了解。SQL Server在工作日有问题,因为它们可能会受到国际化设置的影响。假设为默认值,您可以执行以下操作: select dateadd(day, 1 - datepart(weekday, datefromparts(@year, 12, 31)), datefromparts(@year, 12, 31)
我对TSQL不太了解。SQL Server在工作日有问题,因为它们可能会受到国际化设置的影响。假设为默认值,您可以执行以下操作:
select dateadd(day,
1 - datepart(weekday, datefromparts(@year, 12, 31)),
datefromparts(@year, 12, 31)
)
否则,您需要执行一个case
表达式来将一周中的某一天转换为一个数字
在较旧版本的SQL Server中,您可以执行以下操作:
select dateadd(day,
1 - datepart(weekday, cast(@year + '0101' as date)),
cast(@year + '0101' as date)
)
我没有专门使用过tsql,但如果我的sql知识和谷歌搜索足够好,那么像这样的东西应该可以做到:
... WHERE DATEPART(dw, date) = 7 and DATEDIFF (d, date, DATEFROMPARTS (DATEPART(yyyy, date), 12, 31)) <= 6
。。。其中DATEPART(dw,date)=7和DATEDIFF(d,date,DATEFROMPARTS(DATEPART(yyyy,date),12,31))使用Gordon先生的查询,在IIF()之后如果给定的日期是一年中的最后一个星期日,则返回1;如果不是,则返回0
使用2018作为年份,使用2018-12-30作为给定日期。可以用变量替换值
select IIF( DATEDIFF(DAY,'2018-12-30',
DATEADD(day,
1 - datepart(weekday, datefromparts(2018, 12, 31)),
datefromparts(2018, 12, 31)
)) = 0, 1, 0)
你可以使用这个功能
功能代码:
create FUNCTION CheckIsSaturday
(
@date DATETIME
)
RETURNS int
AS
BEGIN
-- Declare the return variable here
DECLARE @result INT
DECLARE @DayOfWeek NVARCHAR(22)
DECLARE @LastDayOfYear DATETIME
select @LastDayOfYear=DATEADD(yy, DATEDIFF(yy, 0, @date) + 1, -1)
SELECT @DayOfWeek=DATENAME(dw, @date)
IF(@DayOfWeek='Saturday' AND DATEDIFF(dd,@date,@LastDayOfYear)<7)
RETURN 1;
RETURN 0;
END
GO
如果您有一个
您还可以使用此功能获取一年中的每一天:
;WITH getlastdaysofyear ( LastDay, DayCnt ) AS (
SELECT DATEADD(dd, -DAY(DATEADD(mm, 1, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1))),
DATEADD(mm, 1, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1))),
0 AS DayCnt
UNION ALL
SELECT LastDay,
DayCnt + 1
FROM getlastdaysofyear
)
SELECT *
FROM ( SELECT TOP 7 DATEADD(DD, -DayCnt, LastDay) LastDate,
'Last ' + DATENAME(Weekday,DATEADD(DD, -DayCnt, LastDay)) AS DayStatus
FROM getlastdaysofyear ) T
ORDER BY DATEPART(Weekday, LastDate)
希望您喜欢:)我将年份声明为int,然后尝试上面的查询,结果显示无法构造数据类型date,一些参数的值无效@gordon在这里似乎可以正常工作。什么版本的SQL Server?很好的简单解决方案。可能与
DECLARE @CheckDate DATE = '20181230'
;WITH cteGetDates AS
(
SELECT
[Date], WeekDayName, WeekOfMonth, [MonthName], [Year]
,LastDOWInMonth = ROW_NUMBER() OVER
(
PARTITION BY FirstDayOfMonth, [Weekday]
ORDER BY [Date] DESC
)
FROM
dbo.DateDimension
)
SELECT * FROM cteGetDates D
WHERE D.LastDOWInMonth = 1 AND D.WeekDayName = 'Sunday' and D.MonthName = 'December' AND D.[Date] = @CheckDate
;WITH getlastdaysofyear ( LastDay, DayCnt ) AS (
SELECT DATEADD(dd, -DAY(DATEADD(mm, 1, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1))),
DATEADD(mm, 1, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1))),
0 AS DayCnt
UNION ALL
SELECT LastDay,
DayCnt + 1
FROM getlastdaysofyear
)
SELECT *
FROM ( SELECT TOP 7 DATEADD(DD, -DayCnt, LastDay) LastDate,
'Last ' + DATENAME(Weekday,DATEADD(DD, -DayCnt, LastDay)) AS DayStatus
FROM getlastdaysofyear ) T
ORDER BY DATEPART(Weekday, LastDate)