Sql 请注意，如果有2个或更多的产品id创建的日期不同，但最高金额相同，它们都将被退回。“我没有考虑过这种情况，谢谢 WITH cte AS ( SELECT * , RANK() OVER (PARTITION BY product_id ORDER BY

请注意，如果有2个或更多的产品id创建的日期不同，但最高金额相同，它们都将被退回。“我没有考虑过这种情况，谢谢

WITH cte AS
(
  SELECT * , RANK() OVER (PARTITION BY product_id ORDER BY amount DESC) AS rnk
  FROM Offers
)
SELECT id, product_id, created_at, amount
FROM cte
WHERE rnk = 1
ORDER BY amount DESC;

select distinct on (product_id) o.*
from offers o
order by product_id, amount desc;

SELECT o.*
FROM offer o
LEFT JOIN offer o1 ON o1.amount > o.amount AND o.product_id = o1.product_id
WHERE o1.amount IS NULL