Sql 分区上的SUM（）-聚合函数的使用无效

我有一个查询，它在下面的示例中运行良好

    Select t2.leadno
    , t1.quoteno
    , t1.cn_ref
    , sum(t1.qty/100)
    , ROW_NUMBER() Over (Partition By t2.leadno order by sum(qty/100) desc) as RN 
From dba.quotelne as t1 
    LEFT JOIN dba.quotehdr as t2 ON t1.quoteno = t2.quoteno
Where leadno = 31665 
    and t1.statusflag = 'A' 
    and t2.statusflag = 'A' 
Group By t2.leadno
    , t1.quoteno
    , t1.cn_ref

一旦我告诉你，试着过滤这个，只显示RN=1，如下所示，给我一个错误

“聚合函数的使用无效”

我所做的只是将RN=1添加到where语句中，我缺少什么

我正在使用Adaptive Server Anywhere 9.0，我想您需要：

Select Top 1 t2.leadno
    , t1.quoteno
    , t1.cn_ref
    , sum(t1.qty/100)
    , ROW_NUMBER() Over (Partition By t2.leadno order by sum(qty/100) desc) as RN 
From dba.quotelne as t1 
    LEFT JOIN dba.quotehdr as t2 ON t1.quoteno = t2.quoteno
Where leadno = 31665 
    and t1.statusflag = 'A' 
    and t2.statusflag = 'A'
Group By t2.leadno
    , t1.quoteno
    , t1.cn_ref
Order By RN

---

不能在

中使用
中定义的列别名，在
中选择
，其中
处于同一级别。这与窗口函数无关。这是所有列的规则。因此，使用子查询：

select t.*
from (Select t2.leadno, t1.quoteno, t1.cn_ref, sum(t1.qty/100),
             ROW_NUMBER() Over (Partition By t2.leadno order by sum(qty/100) desc) as RN 
      From dba.quotelne t1 INNER JOIN
           dba.quotehdr t2
           ON t1.quoteno = t2.quoteno
      Where leadno = 31665 and t1.statusflag = 'A' and t2.statusflag = 'A' 
      Group By t2.leadno, t1.quoteno, t1.cn_ref
     ) t
where rn = 1;

注意：您的
左连接
是不必要的，因为
WHERE
子句将其转换为
内部连接
。因此，我将其更改为
内部联接

select t.*
from (Select t2.leadno, t1.quoteno, t1.cn_ref, sum(t1.qty/100),
             ROW_NUMBER() Over (Partition By t2.leadno order by sum(qty/100) desc) as RN 
      From dba.quotelne t1 INNER JOIN
           dba.quotehdr t2
           ON t1.quoteno = t2.quoteno
      Where leadno = 31665 and t1.statusflag = 'A' and t2.statusflag = 'A' 
      Group By t2.leadno, t1.quoteno, t1.cn_ref
     ) t
where rn = 1;