Oracle SQL-按一定顺序列出父表和子表中的记录

我有两个表T1（父表）和T2（子表）

T1:

T2:

预期产出：

ID | File | ASSURANCE | VAL |
 1 |  L1  |   ASSR1   |  0  | - Matched row from T1 for id=1 and lang=l1 
 1 |  F1  |   ASSR1   |  0  | - Matched row from T2 for id=1 and lang=l1 
 1 |  F2  |   ASSR1   |  4  | - Matched row from T2 for id=1 and lang=l1 
 1 |  L2  |   ASSR2   |  1  | - Matched row from T1 for id=1 and lang=l2
 1 |  F3  |   ASSR2   |  8  | - Matched row from T2 for id=1 and lang=l2
 1 |  F4  |   ASSR2   |  3  | - Matched row from T2 for id=1 and lang=l2
 1 |  L3  |   ASSR3   |  5  | - Matched row from T1 for id=1 and lang=l3
 1 |  F5  |   ASSR3   |  7  | - Matched row from T2 for id=1 and lang=l3
 1 |  F6  |   ASSR3   |  0  | - Matched row from T2 for id=1 and lang=l3

要求：

对于id=1，我希望遍历T1，对于每个lang，我希望首先输出该行（从T1），然后在T2中遍历id和当前lang，以及T2中匹配的记录列表（对于id和当前lang） 然后继续T1中的下一个lang，直到在T1中处理完所有lang

是否可以使用单个Oracle SQL查询来实现它

谢谢。

像这样的吗

SQL> with t1 (id, lang, assurance, val) as
  2  (select 1, 'L1', 'assr1', 0 from dual union all
  3   select 1, 'L2', 'assr2', 1 from dual union all
  4   select 1, 'L3', 'assr3', 5 from dual
  5  ),
  6    t2 (id, lang, cfile, assurance, val) as
  7  (select 1, 'L1', 'F1', 'assr1', 0 from dual union all
  8   select 1, 'L1', 'F2', 'assr1', 4 from dual union all
  9   select 1, 'L2', 'F3', 'assr2', 8 from dual union all
 10   select 1, 'L2', 'F4', 'assr2', 3 from dual union all
 11   select 1, 'L3', 'F5', 'assr3', 7 from dual union all
 12   select 1, 'L3', 'F6', 'assr3', 0 from dual
 13  ),
 14    inter as
 15  (select t1.id, t1.lang, t1.lang cfile, t1.assurance, t1.val from t1
 16   union all
 17   select t2.id, t2.lang, t2.cfile, t2.assurance, t2.val from t2
 18  )
 19  select id, cfile, assurance, val
 20  from inter
 21  order by id, lang, cfile desc;

        ID CF ASSUR        VAL
---------- -- ----- ----------
         1 L1 assr1          0
         1 F2 assr1          4
         1 F1 assr1          0
         1 L2 assr2          1
         1 F4 assr2          3
         1 F3 assr2          8
         1 L3 assr3          5
         1 F6 assr3          0
         1 F5 assr3          7

9 rows selected.

SQL>

像这样的

SQL> with t1 (id, lang, assurance, val) as
  2  (select 1, 'L1', 'assr1', 0 from dual union all
  3   select 1, 'L2', 'assr2', 1 from dual union all
  4   select 1, 'L3', 'assr3', 5 from dual
  5  ),
  6    t2 (id, lang, cfile, assurance, val) as
  7  (select 1, 'L1', 'F1', 'assr1', 0 from dual union all
  8   select 1, 'L1', 'F2', 'assr1', 4 from dual union all
  9   select 1, 'L2', 'F3', 'assr2', 8 from dual union all
 10   select 1, 'L2', 'F4', 'assr2', 3 from dual union all
 11   select 1, 'L3', 'F5', 'assr3', 7 from dual union all
 12   select 1, 'L3', 'F6', 'assr3', 0 from dual
 13  ),
 14    inter as
 15  (select t1.id, t1.lang, t1.lang cfile, t1.assurance, t1.val from t1
 16   union all
 17   select t2.id, t2.lang, t2.cfile, t2.assurance, t2.val from t2
 18  )
 19  select id, cfile, assurance, val
 20  from inter
 21  order by id, lang, cfile desc;

        ID CF ASSUR        VAL
---------- -- ----- ----------
         1 L1 assr1          0
         1 F2 assr1          4
         1 F1 assr1          0
         1 L2 assr2          1
         1 F4 assr2          3
         1 F3 assr2          8
         1 L3 assr3          5
         1 F6 assr3          0
         1 F5 assr3          7

9 rows selected.

SQL>

试试这个：

with 
    T1 as (
            select 1 as id, 'L1' as LANG, 'ASSR1' as assurance, 0 as VAL from dual union
            select 1, 'L2', 'ASSR2',1 from dual union
            select 1, 'L3','ASSR3',5 from dual),
    T2 as (
            select 1 as id , 'L1' as lang, 'F1' as "FILE", 'ASSR1' as assurance, 0 as val from dual union
            select 1,'L1','F2','ASSR1',4 from dual union
            select 1,'L2','F3','ASSR2',8 from dual union
            select 1,'L2','F4','ASSR2',3 from dual union
            select 1,'L3','F5','ASSR3',7 from dual union
            select 1,'L3','F6','ASSR3',0 from dual),
    T3 as (select t2.id, t2.lang, t2."FILE", t2.assurance, t2.val, row_number() over (partition by t2.id, t2.lang order by t2."FILE") as pos
           from T2    
             inner join t1 on t1.id = t2.id and t1.lang = t2.lang)
select t1.id, t1.lang, t1.lang as "FILE", t1.assurance, t1.val, 0 as pos from T1
union
select t3.id, t3.lang, t3."FILE", t3.assurance, t3.val,  t3.pos
from t3
order by id,lang,pos

输出：

ID  LANG    FILE    ASSURANCE   VAL POS
1   L1  L1  ASSR1   0   0
1   L1  F1  ASSR1   0   1
1   L1  F2  ASSR1   4   2
1   L2  L2  ASSR2   1   0
1   L2  F3  ASSR2   8   1
1   L2  F4  ASSR2   3   2
1   L3  L3  ASSR3   5   0
1   L3  F5  ASSR3   7   1
1   L3  F6  ASSR3   0   2

试试这个：

with 
    T1 as (
            select 1 as id, 'L1' as LANG, 'ASSR1' as assurance, 0 as VAL from dual union
            select 1, 'L2', 'ASSR2',1 from dual union
            select 1, 'L3','ASSR3',5 from dual),
    T2 as (
            select 1 as id , 'L1' as lang, 'F1' as "FILE", 'ASSR1' as assurance, 0 as val from dual union
            select 1,'L1','F2','ASSR1',4 from dual union
            select 1,'L2','F3','ASSR2',8 from dual union
            select 1,'L2','F4','ASSR2',3 from dual union
            select 1,'L3','F5','ASSR3',7 from dual union
            select 1,'L3','F6','ASSR3',0 from dual),
    T3 as (select t2.id, t2.lang, t2."FILE", t2.assurance, t2.val, row_number() over (partition by t2.id, t2.lang order by t2."FILE") as pos
           from T2    
             inner join t1 on t1.id = t2.id and t1.lang = t2.lang)
select t1.id, t1.lang, t1.lang as "FILE", t1.assurance, t1.val, 0 as pos from T1
union
select t3.id, t3.lang, t3."FILE", t3.assurance, t3.val,  t3.pos
from t3
order by id,lang,pos

输出：

ID  LANG    FILE    ASSURANCE   VAL POS
1   L1  L1  ASSR1   0   0
1   L1  F1  ASSR1   0   1
1   L1  F2  ASSR1   4   2
1   L2  L2  ASSR2   1   0
1   L2  F3  ASSR2   8   1
1   L2  F4  ASSR2   3   2
1   L3  L3  ASSR3   5   0
1   L3  F5  ASSR3   7   1
1   L3  F6  ASSR3   0   2

---

使用

union all

粘合表，添加有关行源的信息。对于第一个表，还将列

lang

添加为

文件

。终于把这个联盟整理好了

select id, file_, assurance, val
  from (
    select id, lang, lang file_, assurance, val, 't1' source from t1 where id = 1
    union all
    select id, lang, file_, assurance, val, 't2' source from t2 where id = 1)
  order by lang, source, file_

---

使用

union all

粘合表，添加有关行源的信息。对于第一个表，还将列

lang

添加为

文件

。终于把这个联盟整理好了

select id, file_, assurance, val
  from (
    select id, lang, lang file_, assurance, val, 't1' source from t1 where id = 1
    union all
    select id, lang, file_, assurance, val, 't2' source from t2 where id = 1)
  order by lang, source, file_