如果SQL中存在某些字符，则从字符串中提取子字符串

我有一个字符串：

DECLARE @UserComment AS VARCHAR(1000) = 'bjones marked inspection on system UP for site COL01545 as Refused to COD won''t pay upfront  :Routeid: 12 :Inspectionid: 55274'

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“Inspectionid:'只留下要保存到变量中的Inspectionid”之后，我是否可以从字符串中提取所有内容？

您的示例工作不太正确。您将变量定义为varchar（100），但字符串中的字符比这个多

这应该基于您的示例数据

DECLARE @UserComment AS VARCHAR(1000) = 'bjones marked inspection on system UP for site COL01545 as Refused to COD won''t pay upfront  :Routeid: 12 :Inspectionid: 55274'

select right(@UserComment, case when charindex('Inspectionid: ', @UserComment, 0) > 0 then len(@UserComment) - charindex('Inspectionid: ', @UserComment, 0) - 13 else len(@UserComment) end)

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你的例子不太正确。您将变量定义为varchar（100），但字符串中的字符比这个多

这应该基于您的示例数据

DECLARE @UserComment AS VARCHAR(1000) = 'bjones marked inspection on system UP for site COL01545 as Refused to COD won''t pay upfront  :Routeid: 12 :Inspectionid: 55274'

select right(@UserComment, case when charindex('Inspectionid: ', @UserComment, 0) > 0 then len(@UserComment) - charindex('Inspectionid: ', @UserComment, 0) - 13 else len(@UserComment) end)

我会这样做：

select stuff(@UserComment, 1, charindex(':Inspectionid: ', @UserComment) + 14, '')

即使找不到字符串，也可以这样做——尽管它将返回整个字符串。要在这种情况下获取空字符串，请执行以下操作：

select stuff(@UserComment, 1, charindex(':Inspectionid: ', @UserComment + ':Inspectionid: ') + 14, '')

我会这样做：

select stuff(@UserComment, 1, charindex(':Inspectionid: ', @UserComment) + 14, '')

即使找不到字符串，也可以这样做——尽管它将返回整个字符串。要在这种情况下获取空字符串，请执行以下操作：

select stuff(@UserComment, 1, charindex(':Inspectionid: ', @UserComment + ':Inspectionid: ') + 14, '')

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首先，我要说的是@UserComment变量不够长，无法包含要输入的文本。增加第一个的大小

下面的SQL将提取该值：

DECLARE @UserComment AS VARCHAR(1000); SET @UserComment = 'bjones marked inspection on system UP for site COL01545 as Refused to COD won''t pay upfront  :Routeid: 12 :Inspectionid: 55274'

DECLARE @pos int
DECLARE @InspectionId int
DECLARE @IdToFind varchar(100)

SET @IdToFind = 'Inspectionid: '
SET @pos = CHARINDEX(@IdToFind, @UserComment)
IF @pos > 0
BEGIN
    SET @InspectionId = CAST(SUBSTRING(@UserComment, @pos+LEN(@IdToFind)+1, (LEN(@UserComment) - @pos) + 1) AS INT)
    PRINT @InspectionId
END

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如果需要，您可以将上述代码转换成SQL函数。

首先，我要说的是@UserComment变量不够长，无法包含您输入的文本。增加第一个的大小

下面的SQL将提取该值：

DECLARE @UserComment AS VARCHAR(1000); SET @UserComment = 'bjones marked inspection on system UP for site COL01545 as Refused to COD won''t pay upfront  :Routeid: 12 :Inspectionid: 55274'

DECLARE @pos int
DECLARE @InspectionId int
DECLARE @IdToFind varchar(100)

SET @IdToFind = 'Inspectionid: '
SET @pos = CHARINDEX(@IdToFind, @UserComment)
IF @pos > 0
BEGIN
    SET @InspectionId = CAST(SUBSTRING(@UserComment, @pos+LEN(@IdToFind)+1, (LEN(@UserComment) - @pos) + 1) AS INT)
    PRINT @InspectionId
END

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如有必要，您可以将上述代码转换为SQL函数。

如果检查ID始终为5位数字，则子字符串函数（长度）的最后一个参数可以为5，即

SELECT SUBSTRING(@UserComment,PATINDEX('%Inspectionid:%',@UserComment)+14,5)

如果检查ID不同（但总是在末尾-您的问题略微暗示了这一点），那么可以通过从字符串的总长度中减去'InspectionID'的位置来导出最后一个参数。像这样：

SELECT SUBSTRING(@UserComment,PATINDEX('%Inspectionid:%',@UserComment)+14,LEN(@usercomment)-(PATINDEX('%Inspectionid:%',@UserComment)+13))

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如果检验ID始终为5位数字，则子字符串函数（长度）的最后一个参数可以为5，即

SELECT SUBSTRING(@UserComment,PATINDEX('%Inspectionid:%',@UserComment)+14,5)

如果检查ID不同（但总是在末尾-您的问题略微暗示了这一点），那么可以通过从字符串的总长度中减去'InspectionID'的位置来导出最后一个参数。像这样：

SELECT SUBSTRING(@UserComment,PATINDEX('%Inspectionid:%',@UserComment)+14,LEN(@usercomment)-(PATINDEX('%Inspectionid:%',@UserComment)+13))

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我继续往前走，把柱子修好了。尽管如此，你的回答还是很有效。谢谢我继续往前走，把柱子修好了。尽管如此，你的回答还是很有效。谢谢