Sql 列'；dbo.mdSpaceSales.wkid'；在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中

我得到了以下查询的上述错误：

SELECT 
    a.stid, a.pfid, pf.pfname, a.mdid, 
    mm.mdDescription, a.categoryid, a.SummedSpace,
    a.AvgSpace, mm.size_sqft as MML_size, a.TotalRev,
    a.TotalProfit, a.wkCount, a.Lastwkinst 
FROM
   (SELECT wkid, stid, mdid, pfid, categoryid,
           sum([space]) as SummedSpace, avg([space]) as AvgSpace,
           sum(revenue) as TotalRev, sum(profit) as TotalProfit,
           count(wkid) as wkCount, max(wkid) as Lastwkinst
    FROM dbo.mdSpaceSales
    WHERE wkid > 200936 AND categoryid in (25, 16, 62, 4079)
    GROUP BY stid, mdid, pfid, categoryid) AS a
LEFT JOIN mdmasterlist mm ON mm.mdid = a.mdid
LEFT JOIN 
    (SELECT distinct pfid, [pf name] as pfname FROM mdmasterlist) AS pf
       ON pf.pfid = a.pfid
ORDER BY 
    stid, categoryid, a.pfid, a.mdid

---

有人能帮我解决这个错误吗？

在子查询中，您说：

SELECT wkid,stid,mdid,pfid,categoryid,SUM()... 
group by stid,mdid,pfid,categoryid

我认为需要：

SELECT wkid,stid,mdid,pfid,categoryid,SUM()... 
group by wkid,stid,mdid,pfid,categoryid

否则，您将尝试让SQL Server猜测您希望在选择列表中使用哪个wkid。也许您的目的是不中断每个wkid（因为您似乎没有在外部查询中公开它），在这种情况下，它应该是：

SELECT stid,mdid,pfid,categoryid,SUM()... 
group by stid,mdid,pfid,categoryid

---

在子查询中，您可以说：

SELECT wkid,stid,mdid,pfid,categoryid,SUM()... 
group by stid,mdid,pfid,categoryid

我认为需要：

SELECT wkid,stid,mdid,pfid,categoryid,SUM()... 
group by wkid,stid,mdid,pfid,categoryid

否则，您将尝试让SQL Server猜测您希望在选择列表中使用哪个wkid。也许您的目的是不中断每个wkid（因为您似乎没有在外部查询中公开它），在这种情况下，它应该是：

SELECT stid,mdid,pfid,categoryid,SUM()... 
group by stid,mdid,pfid,categoryid

---

内部派生查询：必须分组（折叠）或聚合wkid

您正在尝试两种方法：

选择wkid计数（wkid）max（wkid）按stid、mdid、pfid、类别分组

我怀疑您需要删除第一个wkid，因此：

...
FROM
   (SELECT /*wkid drop me*/, stid, mdid, pfid, categoryid,
           sum([space]) as SummedSpace, avg([space]) as AvgSpace,
           sum(revenue) as TotalRev, sum(profit) as TotalProfit,
           count(wkid) as wkCount, max(wkid) as Lastwkinst
    FROM dbo.mdSpaceSales
    WHERE wkid > 200936 AND categoryid in (25, 16, 62, 4079)
    GROUP BY stid, mdid, pfid, categoryid) AS a
LEFT JOIN
...

---

聚合的一个简单规则：必须能够用普通语言表达查询。

内部派生查询：必须分组（折叠）或聚合wkid

您正在尝试两种方法：

选择wkid计数（wkid）max（wkid）按stid、mdid、pfid、类别分组

我怀疑您需要删除第一个wkid，因此：

...
FROM
   (SELECT /*wkid drop me*/, stid, mdid, pfid, categoryid,
           sum([space]) as SummedSpace, avg([space]) as AvgSpace,
           sum(revenue) as TotalRev, sum(profit) as TotalProfit,
           count(wkid) as wkCount, max(wkid) as Lastwkinst
    FROM dbo.mdSpaceSales
    WHERE wkid > 200936 AND categoryid in (25, 16, 62, 4079)
    GROUP BY stid, mdid, pfid, categoryid) AS a
LEFT JOIN
...

聚合的一个简单规则：您必须能够用普通语言表达查询