SQL Server累计用户数天数
我有这样一个用户表:SQL Server累计用户数天数,sql,sql-server,azure-sql-database,Sql,Sql Server,Azure Sql Database,我有这样一个用户表: id | createdAt | name ... ---+--------------------------------+----------- 1 2017-04-12 13:19:37.287 +00:00 X 2 2017-04-12 13:19:37.287 +00:00 Y 3 2017-04-12 13:19:37.287 +00:00 Z 4 2017-04-13 13:
id | createdAt | name ...
---+--------------------------------+-----------
1 2017-04-12 13:19:37.287 +00:00 X
2 2017-04-12 13:19:37.287 +00:00 Y
3 2017-04-12 13:19:37.287 +00:00 Z
4 2017-04-13 13:19:37.287 +00:00 T
5 2017-04-13 13:19:37.287 +00:00 W
6 2017-04-14 13:19:37.287 +00:00 W
7 2017-04-14 13:19:37.287 +00:00 W
day | count
-----------+--------
2017-04-12 3
2017-04-13 5
2017-04-14 7
我需要的是每天的累积用户数,如下所示:
id | createdAt | name ...
---+--------------------------------+-----------
1 2017-04-12 13:19:37.287 +00:00 X
2 2017-04-12 13:19:37.287 +00:00 Y
3 2017-04-12 13:19:37.287 +00:00 Z
4 2017-04-13 13:19:37.287 +00:00 T
5 2017-04-13 13:19:37.287 +00:00 W
6 2017-04-14 13:19:37.287 +00:00 W
7 2017-04-14 13:19:37.287 +00:00 W
day | count
-----------+--------
2017-04-12 3
2017-04-13 5
2017-04-14 7
我试着用这个SQL语句对几天进行分组,但它只得到当天的记录,而不是累计记录
SELECT
CAST(createdAt AS DATE) AS date, COUNT(*) AS userCount
FROM
dbo.Users
GROUP BY
CAST(createdAt AS DATE)
ORDER BY
CAST(createdAt AS DATE) DESC
谢谢你的帮助
感谢您在SQL Server 2012+中使用累计总和:
SELECT CAST(createdAt AS DATE) as date, COUNT(*) as userCount,
SUM(COUNT(*)) OVER (ORDER BY CAST(createdAt AS DATE)) as cumulative_count
FROM dbo.Users u
GROUP BY CAST(createdAt AS DATE)
ORDER BY CAST(createdAt AS DATE) DESC;
在早期版本中,还需要其他一些方法,例如关联子查询:
WITH u as (
SELECT CAST(createdAt AS DATE) as date, COUNT(*) as userCount
FROM dbo.Users u
GROUP BY CAST(createdAt AS DATE)
)
SELECT u.*,
(SELECT SUM(usrCount)
FROM u u2
WHERE u2.date <= u.date
) as cumulative_count
FROM u
ORDER BY date DESC;
您正在使用哪个版本的SQL Server?Azure SQL@GordonLinoff