无法使用SQL查询来计算行数

这总是返回0。我有一个表tblArticles，它有一个AuthorID和ID主键用于文章

然后我有一个article投票表，其中有一个articleID列

给定用户13405，我需要找出他们在所有文章中的投票数

---

只是确认一下，Tbalaticleotes中目前有一条记录的articleID为5。文章ID 5的作者ID为13405。

嗯。。。联接中的AuthorID看起来很奇怪。。。也许这样效果更好

SELECT 
  COUNT(*) AS TotalUserVotes
FROM tblArticleVotes AS v 
INNER JOIN tblArticles AS a 
  ON v.ArticleID = a.ID 
     AND a.AuthorID = 13405

---

嗯。。。联接中的AuthorID看起来很奇怪。。。也许这样效果更好

SELECT 
  COUNT(*) AS TotalUserVotes
FROM tblArticleVotes AS v 
INNER JOIN tblArticles AS a 
  ON v.ArticleID = a.ID 
     AND a.AuthorID = 13405

---

尝试将和更改为以下位置：

SELECT COUNT(*) AS TotalUserVotes
  FROM tblArticleVotes AS v INNER JOIN
  tblArticles AS a ON v.ArticleID = a.ID
  WHERE a.AuthorID = 13405

---

HTH

尝试将和更改为以下位置：

SELECT COUNT(*) AS TotalUserVotes
  FROM tblArticleVotes AS v INNER JOIN
  tblArticles AS a ON v.ArticleID = a.ID
  WHERE a.AuthorID = 13405

HTH

试试这个：

SELECT COUNT(*) AS TotalUserVotes
FROM tblArticleVotes AS v INNER JOIN
tblArticles AS a ON v.ArticleID = a.ID WHERE a.AuthorID = 13405

请尝试以下方法：

SELECT COUNT(*) AS TotalUserVotes
FROM tblArticleVotes AS v INNER JOIN
tblArticles AS a ON v.ArticleID = a.ID WHERE a.AuthorID = 13405

---

你的问题没有错。要解决此问题，请将查询打断

SELECT a.AuthorID, COUNT(v.id) as votes
FROM tblArticles AS a 
LEFT JOIN tblArticleVotes AS v ON a.ID = v.ArticleID
GROUP BY a.ID
WHERE a.AuthorID = :author_id

---

你的问题没有错。要解决此问题，请将查询打断

SELECT a.AuthorID, COUNT(v.id) as votes
FROM tblArticles AS a 
LEFT JOIN tblArticleVotes AS v ON a.ID = v.ArticleID
GROUP BY a.ID
WHERE a.AuthorID = :author_id

---

您确定tblArticles中有作者id正确且至少有一票的行吗？您可能希望向问题中添加一些示例数据行。您确定tblArticles中有任何行具有正确的作者id和至少一张投票票吗？您可能希望向问题中添加一些示例数据行。这与原始查询有何不同？除了sql语句的符号之外，它们不应该执行到相同的结果集吗？这与原始查询有什么不同？除了sql语句的符号之外，它们不应该执行到相同的结果集吗？