Sql 加入表后按计数排序

我下面的代码目前有效，但在添加

COUNT

之后

ORDER BY

后，它给了我错误

无效的列名“Answers”

我试图将（Test2.Answers\u for\u考试）计数为第1行中的答案，但也给出了相同的错误消息。 我也可以不显示未找到解决方案的列。我只是在那里添加了它，以便我看到结果，但不需要看到它

在“答案”列下有重复的字符串。我想按最多的字符串数排序。例如：汽车，汽车，纸，石头，纸，纸。我希望首先返回纸张，然后返回car，然后返回rock，因为纸张有3个计数，car有2个计数，rock只有1个计数（假设只有3个唯一的字符串）。如果我按答案顺序描述，他们将按字母顺序排列

使用

COUNT（*）OVER（）

窗口函数执行所需的计数，然后按其排序

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(*) OVER (PARTITION BY Test2.Answers_for_exam) AS AnswerCount
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
ORDER BY AnswerCount DESC

使用

COUNT（*）OVER（）

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(*) OVER (PARTITION BY Test2.Answers_for_exam) AS AnswerCount
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
ORDER BY AnswerCount DESC

您应该在一个单独的列中记录答案的数量（此处为
cnt
），然后按如下顺序排列

SELECT 
    SOLUTION_NOT_FOUND,
    SEARCH_TEST,
    Search_Words,
    Answers
FROM
(
SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(Test2.Answers_for_exam) over ( order by (select 1)) as cnt
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
)T 
ORDER BY cnt DESC

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
GROUP BY 
        Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam
ORDER BY COUNT(Test2.Answers_for_exam) DESC

您也可以像下面这样使用group by

SELECT 
    SOLUTION_NOT_FOUND,
    SEARCH_TEST,
    Search_Words,
    Answers
FROM
(
SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(Test2.Answers_for_exam) over ( order by (select 1)) as cnt
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
)T 
ORDER BY cnt DESC

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
GROUP BY 
        Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam
ORDER BY COUNT(Test2.Answers_for_exam) DESC

您应该在一个单独的列中记录答案的数量（此处为
cnt
），然后按如下顺序排列

SELECT 
    SOLUTION_NOT_FOUND,
    SEARCH_TEST,
    Search_Words,
    Answers
FROM
(
SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(Test2.Answers_for_exam) over ( order by (select 1)) as cnt
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
)T 
ORDER BY cnt DESC

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
GROUP BY 
        Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam
ORDER BY COUNT(Test2.Answers_for_exam) DESC

您也可以像下面这样使用group by

SELECT 
    SOLUTION_NOT_FOUND,
    SEARCH_TEST,
    Search_Words,
    Answers
FROM
(
SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers,
        COUNT(Test2.Answers_for_exam) over ( order by (select 1)) as cnt
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
)T 
ORDER BY cnt DESC

SELECT  Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam AS Answers
FROM    Test 
INNER JOIN  Test2 ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
GROUP BY 
        Test.SOLUTION_NOT_FOUND, 
        Test.SEARCH_TEST, 
        Test.KEYWORD as Search_Words, 
        Test2.Answers_for_exam
ORDER BY COUNT(Test2.Answers_for_exam) DESC

您可以按

的顺序使用窗口函数。所以，我想你想要：

SELECT Test.SOLUTION_NOT_FOUND, 
       Test.SEARCH_TEST, 
       Test.KEYWORD as Search_Words, 
       Test2.Answers_for_exam AS Answers
FROM Test INNER JOIN
     Test2
     ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
ORDER BY COUNT(*) OVER (PARTITION BY Test2.Answers_for_exam) DESC;

---

这应该是实现目标的最简单方法。

您可以按的顺序使用窗口函数。所以，我想你想要：

SELECT Test.SOLUTION_NOT_FOUND, 
       Test.SEARCH_TEST, 
       Test.KEYWORD as Search_Words, 
       Test2.Answers_for_exam AS Answers
FROM Test INNER JOIN
     Test2
     ON Test.TEST_NUMBER = Test2.TEST_NUMBER
WHERE SOLUTION_NOT_FOUND = 1
ORDER BY COUNT(*) OVER (PARTITION BY Test2.Answers_for_exam) DESC;

---

这应该是实现目标的最简单的方法。

你没有

分组方式

，所以这些都没有意义。这是MySQL吗？这有点疯狂。否则，只需按所需的所有列进行分组（但不包括明显的答案）。当你解决了这个问题后，只需将“答案”更改为

Test2。考试的答案

难题是我没有任何东西可以

分组。从该专栏中获得前10个“答案”是否有解决办法？我使用的是MS SQL Server management Studio。您能否显示表中的数据？您希望得到什么结果？您如何定义
前10个答案
？，请解释。为什么不直接使用“按答案排序描述”

？为什么不尝试选择前10名？如果你只是在这里寻找前10名，你可以使用“按答案排序描述考试描述”？因为你没有“按答案排序描述”，所以这一切都没有意义。这是MySQL吗？这有点疯狂。否则，只需按所需的所有列进行分组（但不包括明显的答案）。当你解决了这个问题后，只需将“答案”更改为

Test2。考试的答案

难题是我没有任何东西可以

分组。从该专栏中获得前10个“答案”是否有解决办法？我使用的是MS SQL Server management Studio。您能否显示表中的数据？您希望得到什么结果？您如何定义
前10个答案
？，请解释。为什么不直接使用“按答案排序描述”

？为什么不尝试选择前10名？如果您只是在这里查找前10名，您可以使用“按答案排序描述考试描述”

LIMIT 10

按计数返回前10名字符串，但出现了“LIMIT”附近的错误语法错误。请您提供建议。我添加了

LIMIT 10

以按计数返回前10个字符串，但出现了“LIMIT”附近的错误错误语法。你能给点建议吗？谢谢！我怎样才能得到前十名的结果？@Jonathan。这是另一个问题。它应该作为一个新问题提出，带有样本数据和期望的结果。谢谢！我怎样才能得到前十名的结果？@Jonathan。这是另一个问题。它应该作为一个新问题提出，包括样本数据和期望的结果。