Sql 仅跳过首次服务日期

我希望跳过每个客户的第一个服务日期，前提是该服务日期与客户的第一个服务日期匹配

例如，如果客户于2017年4月1日登记

客户注册日期服务日期
sam 1-04-2017 1-04-2017 sam 1-04-2017 1-04-2017 jon 1-04-2017 1-04-2017
jon 1-04-2017 1-05-2017 sam 1-04-2017 1-05-2017
jon 1-04-2017 1-07-2017 摘要页面的预期结果

total clients total services 2 4 客户总数服务总数 2 4 希望查看详细信息时的预期结果

客户注册日期服务日期
sam 1-04-2017 1-04-2017 jon 1-04-2017 1-05-2017 sam 1-04-2017 1-05-2017
jon 1-04-2017 1-07-2017

此外，您的客户端有一个注册，但有多个服务。

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考虑到查询将上载到ssrs，并且服务日期将是@begindate和@enddate之间的变量s.begindate，我如何跳过查询中的第一个服务日期

根据您的描述，您似乎想要一个使用窗口函数的简单

where

子句：

select t.*
from (select t.*,
             min(enrollment_date) over (partition by client) as first_enrollment_date
      from t
     ) t
where first_enrollment_date > service_date;

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但是，这将只剩下两项服务，因此不清楚您真正想要什么。

根据您提供的服务，我猜您需要这项服务

CREATE TABLE T (id int identity, client varchar(10), enrollment_date date, service_date date)

--client enrollment date     service date
INSERT INTO T VALUES 
('sam','1-04-2017','1-04-2017'),
('sam','1-04-2017','1-04-2017'),
('jon','1-04-2017','1-04-2017'),
('jon','1-04-2017','1-05-2017'),
('sam','1-04-2017','1-05-2017'),
('jon','1-04-2017','1-07-2017')

DECLARE @StartDate date = '1-04-2017', @EndDate date = '1-07-2017'

SELECT COUNT(DISTINCT client) AS total_clients, COUNT(1)-COUNT(DISTINCT client) AS total_services
FROM T 
WHERE service_date BETWEEN @StartDate AND @EndDate

SELECT DISTINCT T.* 
FROM T T JOIN (SELECT client, MIN(id) AS enroll_id FROM T GROUP BY client) E
ON T.client = E.client
AND T.id <> E.enroll_id
WHERE service_date BETWEEN @StartDate AND @EndDate
ORDER BY 2, 3

DROP TABLE T

这只是从总计数中减去客户机的不同计数，以抵消注册事件

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希望这对您有所帮助。

这两个客户是显而易见的。这三项服务是什么？在这种情况下，“抵消”是什么意思？这是一个非常合理的解释。如果OP能澄清这是他真正想要的，那就太好了。是的，一些额外的细节会很好。我开始编写一些类似于您发布的内容的代码，但随后许多服务日期与注册日期匹配的事实让我感到困惑。我喜欢这样简单的解决方案，但总会有一些事情发生……：）大家好，很抱歉没有提供尽可能多的细节。我已经更新了问题以包含更多的细节。@HenryAmadi数据库中你的日期是否真的有时间？您需要能够区分注册日期和服务日期的内容。或者，它们都只是一个没有时间的数据吗？哦，不，它有12:00 am附加到所有。

select t.*
from (select t.*,
             min(enrollment_date) over (partition by client) as first_enrollment_date
      from t
     ) t
where first_enrollment_date > service_date;

CREATE TABLE T (id int identity, client varchar(10), enrollment_date date, service_date date)

--client enrollment date     service date
INSERT INTO T VALUES 
('sam','1-04-2017','1-04-2017'),
('sam','1-04-2017','1-04-2017'),
('jon','1-04-2017','1-04-2017'),
('jon','1-04-2017','1-05-2017'),
('sam','1-04-2017','1-05-2017'),
('jon','1-04-2017','1-07-2017')

DECLARE @StartDate date = '1-04-2017', @EndDate date = '1-07-2017'

SELECT COUNT(DISTINCT client) AS total_clients, COUNT(1)-COUNT(DISTINCT client) AS total_services
FROM T 
WHERE service_date BETWEEN @StartDate AND @EndDate

SELECT DISTINCT T.* 
FROM T T JOIN (SELECT client, MIN(id) AS enroll_id FROM T GROUP BY client) E
ON T.client = E.client
AND T.id <> E.enroll_id
WHERE service_date BETWEEN @StartDate AND @EndDate
ORDER BY 2, 3

DROP TABLE T

total_clients total_services
------------- --------------
2             4

id          client     enrollment_date service_date
----------- ---------- --------------- ------------
4           jon        2017-01-04      2017-01-05
6           jon        2017-01-04      2017-01-07
2           sam        2017-01-04      2017-01-04
5           sam        2017-01-04      2017-01-05