Sql 数据透视表给出错误的结果

下面的代码给出了如第一幅图所示的结果集

  SELECT     dbo.tbStudent.Name, dbo.tbStudent.RegNo, dbo.tbFee.PID, dbo.tbFee.Purpose, dbo.tbFee.AmountPaid, dbo.tbFee.StudentID, dbo.tbFee.Date, dbo.tbFee.FeeID, 
                      dbo.tbFee.SemID, dbo.tbFee.CourseID, dbo.tbFee.ModeOfPayment, dbo.tbFee.CheckNo, dbo.tbFee.DDNo, dbo.tbFee.HostelDDNo, dbo.tbFee.FRID, 
                      dbo.tbStudent.Parentage, dbo.tbCourse.Name AS Course, ISNULL(dbo.tbSemester.SemName, ' + @st +') AS Semester
FROM         dbo.tbFee INNER JOIN
                      dbo.tbStudent ON dbo.tbFee.StudentID = dbo.tbStudent.StudentID INNER JOIN
                      dbo.tbCourse ON dbo.tbFee.CourseID = dbo.tbCourse.CourseID LEFT OUTER JOIN
                      dbo.tbSemester ON dbo.tbFee.SemID = dbo.tbSemester.SemID  Where tbFee.SemID=1 

但是，使用透视表，我需要以下结果：

我的数据透视表代码是：

SET @values = '';
 If(@SemID=0)
    BEGIN
        SELECT @values = @values +'['+ CAST(PurPose AS varchar(max))+ ']' + ','
        FROM tbFee Where CourseID=@CourseID
        SET @values = SUBSTRING(@values, 1, Len(@values) - 1)
    END
ELSE
    BEGIN
        SELECT @values = @values +'['+ CAST(PurPose AS varchar(max))+ ']' + ','
        FROM tbFee Where SemID=@SemID
        SET @values = SUBSTRING(@values, 1, Len(@values) - 1)
    END

 Declare @st nvarchar(max)
 set @st='''Not Available''';
 declare @q nvarchar(max)
set @q = '
 Select * from(

SELECT     dbo.tbStudent.Name, dbo.tbStudent.RegNo, dbo.tbFee.PID, dbo.tbFee.Purpose, dbo.tbFee.AmountPaid, dbo.tbFee.StudentID, dbo.tbFee.Date, dbo.tbFee.FeeID, 
                      dbo.tbFee.SemID, dbo.tbFee.CourseID, dbo.tbFee.ModeOfPayment, dbo.tbFee.CheckNo, dbo.tbFee.DDNo, dbo.tbFee.HostelDDNo, dbo.tbFee.FRID, 
                      dbo.tbStudent.Parentage, dbo.tbCourse.Name AS Course, ISNULL(dbo.tbSemester.SemName, ' + @st +') AS Semester
FROM         dbo.tbFee INNER JOIN
                      dbo.tbStudent ON dbo.tbFee.StudentID = dbo.tbStudent.StudentID INNER JOIN
                      dbo.tbCourse ON dbo.tbFee.CourseID = dbo.tbCourse.CourseID LEFT OUTER JOIN
                      dbo.tbSemester ON dbo.tbFee.SemID = dbo.tbSemester.SemID  Where tbFee.SemID=1  
          ) as x
          pivot (
    max(AmountPaid)
    for Purpose in (' + @values + ')
) as pvt
'

exec (@q)

我在@Values中获得了Purpose列的值，这是因为行数可以更改。然而，对于具有相同regNo的同一学生，我得到的结果不是单行，而是以下结果：

但我得到的信息如下：

---

在数据透视的源查询中，您应该只指定实际数据透视中涉及的列，即

dbo.tbStudent.Name、dbo.tbStudent.RegNo、dbo.tbFee.Purpose、dbo.tbFee.AmountPaid

SELECT     
dbo.tbStudent.Name, 
dbo.tbStudent.RegNo,
dbo.tbFee.Purpose, 
dbo.tbFee.AmountPaid
FROM         
dbo.tbFee 
INNER JOIN dbo.tbStudent ON dbo.tbFee.StudentID = dbo.tbStudent.StudentID 
INNER JOIN dbo.tbCourse ON dbo.tbFee.CourseID = dbo.tbCourse.CourseID 
LEFT OUTER JOIN dbo.tbSemester ON dbo.tbFee.SemID = dbo.tbSemester.SemID  
Where tbFee.SemID=1

---

如果除了这些列之外还有其他列，它们将被分解到pivot计算中，您将得到相应的多行。

所有这些列也需要出现在结果中，我只是在图片中删除了它们以使其可读。源查询很好。它必须是这样的，因为我需要所有这些列。问题是这些其他列导致您的pivot结果与您预期的不同。您可以先做透视，然后将透视结果连接到其他列