Sql Postgres-如何找到与某列具有最大交点的行

我有一个名为

Protocols

的表，其中包含一个名为

keyWords

的列，类型为

TEXT[]

。 给定一个字符串数组，如何获得

关键字

列与给定数组最大交集的行？

使用该函数（在其他地方也可能有用）：

查询：

with cte as (
    select 
        id, keywords,
        cardinality(array_intersect(keywords, '{a,b,d}')) as common_elements
    from protocols
    )
select * 
from cte
where common_elements = (select max(common_elements) from cte)

如果您不喜欢该功能：

with cte as (
    select id, count(keyword) as common_elements
    from protocols
    cross join unnest(keywords) as keyword
    where keyword = any('{a,b,d}')
    group by 1
    )
select id, keywords, common_elements
from cte
join protocols using(id)
where common_elements = (select max(common_elements) from cte);

使用该功能（在其他地方也可能有用）：

查询：

with cte as (
    select 
        id, keywords,
        cardinality(array_intersect(keywords, '{a,b,d}')) as common_elements
    from protocols
    )
select * 
from cte
where common_elements = (select max(common_elements) from cte)

如果您不喜欢该功能：

with cte as (
    select id, count(keyword) as common_elements
    from protocols
    cross join unnest(keywords) as keyword
    where keyword = any('{a,b,d}')
    group by 1
    )
select id, keywords, common_elements
from cte
join protocols using(id)
where common_elements = (select max(common_elements) from cte);