Sql 如何在oracle10g中将一列数据拆分为多列？

我们有一个包含3列的表，度量、计数、集合和数据如下所示：

            "METRIC"           "COUNT" "SETS"           
            FOR_PEOPLE_LIKE_ME      0   SET1
            FOR_YOUNG_PEOPLE        1   SET1
            GOOD_TASTE              0   SET1
            HIGH_SATISFACTION       2   SET1
            FOR_STATUS_ORIENTED     0   SET1

            FOR_PEOPLE_LIKE_ME      0   SET2
            FOR_YOUNG_PEOPLE        1   SET2
            GOOD_TASTE              0   SET2
            HIGH_SATISFACTION       0   SET2
            FOR_STATUS_ORIENTED     3   SET2

我想按“SET1”和“SET2”分割数据。我应该采用什么方法 使用？我期望的结果是：

    "METRIC"             "SET1"   "SET2"
    FOR_PEOPLE_LIKE_ME      0         0    
    FOR_YOUNG_PEOPLE        1         1
    GOOD_TASTE              0         0    
    HIGH_SATISFACTION       2         0
    FOR_STATUS_ORIENTED     0         3

---

您正在查找筛选的聚合：

select metric, 
       sum(case sets when 'SET1' then "COUNT" end) as SET1,
       sum(case sets when 'SET2' then "COUNT" end) as SET2
from the_table
group by metric;

---

您正在查找筛选的聚合：

select metric, 
       sum(case sets when 'SET1' then "COUNT" end) as SET1,
       sum(case sets when 'SET2' then "COUNT" end) as SET2
from the_table
group by metric;

---

我认为合适的聚合是

sum

@a\u horse\u，没有名字：谢谢你的回复，它没有给出期望的输出，@Shubh:sorry，fixed。我认为合适的聚合是

sum

@a\u horse\u，没有名字：谢谢你的回复，它没有给出期望的输出，@Shubh:sorry，fixed。