Sql 甲骨文中的分组排名_Sql_Oracle

Sql 甲骨文中的分组排名

sql oracle

Sql 甲骨文中的分组排名,sql,oracle,Sql,Oracle,我有一个问题 Select age,qualification,sum(income) as total_income from employee group by age,qualification; 我想根据年龄组和资格组的总收入确定排名比如说 19|Grad|5000|rank:1 19|Grad|4000|rank:2 19|Grad|3000|rank:3 26|Grad|6000|rank:1 26|Grad|5000|rank:2 26|PosG|8000|rank:1 26

我有一个问题

Select age,qualification,sum(income) as total_income  from employee
group by age,qualification;

我想根据年龄组和资格组的总收入确定排名

比如说

19|Grad|5000|rank:1
19|Grad|4000|rank:2
19|Grad|3000|rank:3
26|Grad|6000|rank:1
26|Grad|5000|rank:2
26|PosG|8000|rank:1
26|PosG|6000|rank:2

我能用甲骨文做吗？我尝试了分区方式，但没有找到它。

Oracle 11g R2架构设置：

CREATE TABLE Employees ( Age, Qualification, Income ) AS
          SELECT 19, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 4000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 3000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 6000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 8000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 6000 FROM DUAL;

SELECT Age,
       Qualification,
       Income,
       RANK() OVER ( PARTITION BY Age, Qualification ORDER BY Income DESC ) AS "Rank"
FROM   Employees

| AGE | QUALIFICATION | INCOME | Rank |
|-----|---------------|--------|------|
|  19 |          Grad |   5000 |    1 |
|  19 |          Grad |   4000 |    2 |
|  19 |          Grad |   3000 |    3 |
|  26 |          Grad |   6000 |    1 |
|  26 |          Grad |   5000 |    2 |
|  26 |          PosG |   8000 |    1 |
|  26 |          PosG |   6000 |    2 |

WITH total_incomes AS (
  SELECT Age,
         Qualification,
         SUM( Income ) AS total_income
  FROM   Employees
  GROUP BY
         Age,
         Qualification
)
SELECT Age,
       Qualification,
       total_income,
       RANK() OVER ( ORDER BY total_income DESC ) AS "Rank"
FROM   total_incomes

| AGE | QUALIFICATION | TOTAL_INCOME | Rank |
|-----|---------------|--------------|------|
|  26 |          PosG |        14000 |    1 |
|  19 |          Grad |        12000 |    2 |
|  26 |          Grad |        11000 |    3 |

查询1：

CREATE TABLE Employees ( Age, Qualification, Income ) AS
          SELECT 19, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 4000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 3000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 6000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 8000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 6000 FROM DUAL;

SELECT Age,
       Qualification,
       Income,
       RANK() OVER ( PARTITION BY Age, Qualification ORDER BY Income DESC ) AS "Rank"
FROM   Employees

| AGE | QUALIFICATION | INCOME | Rank |
|-----|---------------|--------|------|
|  19 |          Grad |   5000 |    1 |
|  19 |          Grad |   4000 |    2 |
|  19 |          Grad |   3000 |    3 |
|  26 |          Grad |   6000 |    1 |
|  26 |          Grad |   5000 |    2 |
|  26 |          PosG |   8000 |    1 |
|  26 |          PosG |   6000 |    2 |

WITH total_incomes AS (
  SELECT Age,
         Qualification,
         SUM( Income ) AS total_income
  FROM   Employees
  GROUP BY
         Age,
         Qualification
)
SELECT Age,
       Qualification,
       total_income,
       RANK() OVER ( ORDER BY total_income DESC ) AS "Rank"
FROM   total_incomes

| AGE | QUALIFICATION | TOTAL_INCOME | Rank |
|-----|---------------|--------------|------|
|  26 |          PosG |        14000 |    1 |
|  19 |          Grad |        12000 |    2 |
|  26 |          Grad |        11000 |    3 |

：

CREATE TABLE Employees ( Age, Qualification, Income ) AS
          SELECT 19, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 4000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 3000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 6000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 8000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 6000 FROM DUAL;

SELECT Age,
       Qualification,
       Income,
       RANK() OVER ( PARTITION BY Age, Qualification ORDER BY Income DESC ) AS "Rank"
FROM   Employees

| AGE | QUALIFICATION | INCOME | Rank |
|-----|---------------|--------|------|
|  19 |          Grad |   5000 |    1 |
|  19 |          Grad |   4000 |    2 |
|  19 |          Grad |   3000 |    3 |
|  26 |          Grad |   6000 |    1 |
|  26 |          Grad |   5000 |    2 |
|  26 |          PosG |   8000 |    1 |
|  26 |          PosG |   6000 |    2 |

WITH total_incomes AS (
  SELECT Age,
         Qualification,
         SUM( Income ) AS total_income
  FROM   Employees
  GROUP BY
         Age,
         Qualification
)
SELECT Age,
       Qualification,
       total_income,
       RANK() OVER ( ORDER BY total_income DESC ) AS "Rank"
FROM   total_incomes

| AGE | QUALIFICATION | TOTAL_INCOME | Rank |
|-----|---------------|--------------|------|
|  26 |          PosG |        14000 |    1 |
|  19 |          Grad |        12000 |    2 |
|  26 |          Grad |        11000 |    3 |

查询2：

CREATE TABLE Employees ( Age, Qualification, Income ) AS
          SELECT 19, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 4000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 3000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 6000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 8000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 6000 FROM DUAL;

SELECT Age,
       Qualification,
       Income,
       RANK() OVER ( PARTITION BY Age, Qualification ORDER BY Income DESC ) AS "Rank"
FROM   Employees

| AGE | QUALIFICATION | INCOME | Rank |
|-----|---------------|--------|------|
|  19 |          Grad |   5000 |    1 |
|  19 |          Grad |   4000 |    2 |
|  19 |          Grad |   3000 |    3 |
|  26 |          Grad |   6000 |    1 |
|  26 |          Grad |   5000 |    2 |
|  26 |          PosG |   8000 |    1 |
|  26 |          PosG |   6000 |    2 |

WITH total_incomes AS (
  SELECT Age,
         Qualification,
         SUM( Income ) AS total_income
  FROM   Employees
  GROUP BY
         Age,
         Qualification
)
SELECT Age,
       Qualification,
       total_income,
       RANK() OVER ( ORDER BY total_income DESC ) AS "Rank"
FROM   total_incomes

| AGE | QUALIFICATION | TOTAL_INCOME | Rank |
|-----|---------------|--------------|------|
|  26 |          PosG |        14000 |    1 |
|  19 |          Grad |        12000 |    2 |
|  26 |          Grad |        11000 |    3 |

：

CREATE TABLE Employees ( Age, Qualification, Income ) AS
          SELECT 19, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 4000 FROM DUAL
UNION ALL SELECT 19, 'Grad', 3000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 6000 FROM DUAL
UNION ALL SELECT 26, 'Grad', 5000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 8000 FROM DUAL
UNION ALL SELECT 26, 'PosG', 6000 FROM DUAL;

SELECT Age,
       Qualification,
       Income,
       RANK() OVER ( PARTITION BY Age, Qualification ORDER BY Income DESC ) AS "Rank"
FROM   Employees

| AGE | QUALIFICATION | INCOME | Rank |
|-----|---------------|--------|------|
|  19 |          Grad |   5000 |    1 |
|  19 |          Grad |   4000 |    2 |
|  19 |          Grad |   3000 |    3 |
|  26 |          Grad |   6000 |    1 |
|  26 |          Grad |   5000 |    2 |
|  26 |          PosG |   8000 |    1 |
|  26 |          PosG |   6000 |    2 |

WITH total_incomes AS (
  SELECT Age,
         Qualification,
         SUM( Income ) AS total_income
  FROM   Employees
  GROUP BY
         Age,
         Qualification
)
SELECT Age,
       Qualification,
       total_income,
       RANK() OVER ( ORDER BY total_income DESC ) AS "Rank"
FROM   total_incomes

| AGE | QUALIFICATION | TOTAL_INCOME | Rank |
|-----|---------------|--------------|------|
|  26 |          PosG |        14000 |    1 |
|  19 |          Grad |        12000 |    2 |
|  26 |          Grad |        11000 |    3 |

您可以使用行数函数。也许rank（）函数更好。。。。。