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使用sql server对两个表进行数据透视_Sql_Sql Server - Fatal编程技术网

使用sql server对两个表进行数据透视

使用sql server对两个表进行数据透视,sql,sql-server,Sql,Sql Server,在我的数据库中有两个表,分别名为Topic和solion 我的桌子如下所示 主题表: 第二桌 这两张是我的桌子,我想像下面一样旋转这两张桌子 皮维奥特表 请帮助…因为这里没有逻辑,我创建了自己的:D只是有兴趣将其自动化 我的逻辑是,我将解决方案中的第一个主题“A”放在4行,第二个主题“B”放在3行,第三个主题“A”放在4行,以此类推。将溶液分成4行和3行批次 请查看示例中的注释: ----------- --created some data to test ----------- DECLAR

在我的数据库中有两个表,分别名为Topic和solion

我的桌子如下所示

主题表:

第二桌

这两张是我的桌子,我想像下面一样旋转这两张桌子

皮维奥特表


请帮助…

因为这里没有逻辑,我创建了自己的:D只是有兴趣将其自动化

我的逻辑是,我将解决方案中的第一个主题“A”放在4行,第二个主题“B”放在3行,第三个主题“A”放在4行,以此类推。将溶液分成4行和3行批次

请查看示例中的注释:

-----------
--created some data to test
-----------
DECLARE @Topic TABLE (topic CHAR(1))

INSERT INTO @Topic SELECT 'A'
INSERT INTO @Topic SELECT 'B'
INSERT INTO @Topic SELECT 'C'
INSERT INTO @Topic SELECT 'D'

DECLARE @Solution TABLE (solution CHAR(2))

INSERT INTO @Solution SELECT 'AA'
INSERT INTO @Solution SELECT 'BB'
INSERT INTO @Solution SELECT 'CC'
INSERT INTO @Solution SELECT 'DD'
INSERT INTO @Solution SELECT 'EE'
INSERT INTO @Solution SELECT 'FF'
INSERT INTO @Solution SELECT 'GG'
INSERT INTO @Solution SELECT 'HH'
INSERT INTO @Solution SELECT 'II'
INSERT INTO @Solution SELECT 'JJ'
INSERT INTO @Solution SELECT 'KK'
INSERT INTO @Solution SELECT 'LL'
INSERT INTO @Solution SELECT 'MM'
INSERT INTO @Solution SELECT 'NN'
INSERT INTO @Solution SELECT 'OO'
INSERT INTO @Solution SELECT 'PP'


--DROP TABLE #topicCTE

-----------
--created table which shows what IDs from solution table must get topic
-----------
;WITH topicCTE As (
    SELECT topic, ROW_NUMBER() OVER (ORDER BY topic) AS ID
    FROM @Topic
)
SELECT topic, ID
    , CASE WHEN ID % 2 = 1 THEN (((ID / 2)+1) *4 + (ID / 2) *3)-4 ELSE (((ID / 2)) *4 + (ID / 2) *3)-3 END AS RowsMINID
    , CASE WHEN ID % 2 = 1 THEN (((ID / 2)+1) *4 + (ID / 2) *3) ELSE (((ID / 2)) *4 + (ID / 2) *3) END AS RowsMAXID
INTO #topicCTE
FROM topicCTE

/*Example Result
topic   ID  RowsMINID   RowsMAXID
A       1   0           4
B       2   4           7
C       3   7           11
D       4   11          14
*/

--DROP TABLE #FinalData
-----------
--attached topics to solution
-----------  

;WITH SolutionCTE AS (
SELECT Solution, ROW_NUMBER() OVER (ORDER BY Solution) AS ID
FROM @Solution 
)
SELECT S.Solution, T2.Topic, ROW_NUMBER() OVER (PARTITION BY T2.Topic ORDER BY Solution) AS RowsID
INTO #FinalData
FROM SolutionCTE AS S
CROSS APPLY (
            SELECT * 
            FROM #topicCTE AS T
            WHERE T.RowsMINID < S.ID AND T.RowsMAXID >= S.ID
           ) AS T2

/*Example result
Solution    Topic   RowsID
AA          A       1
BB          A       2
CC          A       3
DD          A       4
EE          B       1
FF          B       2
GG          B       3
*/



-----------
--get columns for pivot from @topic table
-----------
DECLARE @columns VARCHAR(1000) = STUFF((SELECT ',[' + topic + ']' FROM @Topic FOR XML PATH('')), 1, 1, '')

-----------
--create pivot sql command
-----------
DECLARE @sql NVARCHAR(MAX) = N'
SELECT ' + @columns + '
FROM #FinalData
PIVOT
(
    MAX(Solution)
    FOR [Topic] IN (' + @columns + ')
) AS p';

EXECUTE sp_executesql @sql

/*FINAL Results
A   B   C   D
AA  EE  HH  LL
BB  FF  II  MM
CC  GG  JJ  NN
DD      KK  

*/

我想这不是请求的内容,但很有趣地找到了一些解决方案:D

我想连接这两个表,并像透视表一样获得结果。这里我想将主题列值作为透视表中的列。如何连接?是交叉连接吗?但即使是这样,您的预期结果也不像交叉连接。你能回答这个问题吗:为什么EE在B之下而不是在A之下?为什么B有三个值,C有四个值?回答这些问题可能会让我们了解您想要的内容。我想在我的前端的excel工作表中使用此数据透视表进行相关下拉。@jyparask我认为OP遗漏了预期结果中的II和PPAre A、B、C和D列名,或者它们是结果的一部分?
Solution

AA
BB
CC
DD
EE
FF
GG
HH
II
JJ
KK
LL
MM
NN
OO
PP
A             B         C         D

AA            EE         HH       MM

BB            FF         JJ       NN

CC            GG         KK       OO

DD                       LL
-----------
--created some data to test
-----------
DECLARE @Topic TABLE (topic CHAR(1))

INSERT INTO @Topic SELECT 'A'
INSERT INTO @Topic SELECT 'B'
INSERT INTO @Topic SELECT 'C'
INSERT INTO @Topic SELECT 'D'

DECLARE @Solution TABLE (solution CHAR(2))

INSERT INTO @Solution SELECT 'AA'
INSERT INTO @Solution SELECT 'BB'
INSERT INTO @Solution SELECT 'CC'
INSERT INTO @Solution SELECT 'DD'
INSERT INTO @Solution SELECT 'EE'
INSERT INTO @Solution SELECT 'FF'
INSERT INTO @Solution SELECT 'GG'
INSERT INTO @Solution SELECT 'HH'
INSERT INTO @Solution SELECT 'II'
INSERT INTO @Solution SELECT 'JJ'
INSERT INTO @Solution SELECT 'KK'
INSERT INTO @Solution SELECT 'LL'
INSERT INTO @Solution SELECT 'MM'
INSERT INTO @Solution SELECT 'NN'
INSERT INTO @Solution SELECT 'OO'
INSERT INTO @Solution SELECT 'PP'


--DROP TABLE #topicCTE

-----------
--created table which shows what IDs from solution table must get topic
-----------
;WITH topicCTE As (
    SELECT topic, ROW_NUMBER() OVER (ORDER BY topic) AS ID
    FROM @Topic
)
SELECT topic, ID
    , CASE WHEN ID % 2 = 1 THEN (((ID / 2)+1) *4 + (ID / 2) *3)-4 ELSE (((ID / 2)) *4 + (ID / 2) *3)-3 END AS RowsMINID
    , CASE WHEN ID % 2 = 1 THEN (((ID / 2)+1) *4 + (ID / 2) *3) ELSE (((ID / 2)) *4 + (ID / 2) *3) END AS RowsMAXID
INTO #topicCTE
FROM topicCTE

/*Example Result
topic   ID  RowsMINID   RowsMAXID
A       1   0           4
B       2   4           7
C       3   7           11
D       4   11          14
*/

--DROP TABLE #FinalData
-----------
--attached topics to solution
-----------  

;WITH SolutionCTE AS (
SELECT Solution, ROW_NUMBER() OVER (ORDER BY Solution) AS ID
FROM @Solution 
)
SELECT S.Solution, T2.Topic, ROW_NUMBER() OVER (PARTITION BY T2.Topic ORDER BY Solution) AS RowsID
INTO #FinalData
FROM SolutionCTE AS S
CROSS APPLY (
            SELECT * 
            FROM #topicCTE AS T
            WHERE T.RowsMINID < S.ID AND T.RowsMAXID >= S.ID
           ) AS T2

/*Example result
Solution    Topic   RowsID
AA          A       1
BB          A       2
CC          A       3
DD          A       4
EE          B       1
FF          B       2
GG          B       3
*/



-----------
--get columns for pivot from @topic table
-----------
DECLARE @columns VARCHAR(1000) = STUFF((SELECT ',[' + topic + ']' FROM @Topic FOR XML PATH('')), 1, 1, '')

-----------
--create pivot sql command
-----------
DECLARE @sql NVARCHAR(MAX) = N'
SELECT ' + @columns + '
FROM #FinalData
PIVOT
(
    MAX(Solution)
    FOR [Topic] IN (' + @columns + ')
) AS p';

EXECUTE sp_executesql @sql

/*FINAL Results
A   B   C   D
AA  EE  HH  LL
BB  FF  II  MM
CC  GG  JJ  NN
DD      KK  

*/