Sql 我有一个呼叫数据表，我想计算每天呼叫的唯一帐户的数量，并计算每月呼叫的唯一帐户的总和

我有一个表，有两个唯一的列，一个是帐号，另一个是日期。下面给出了示例数据

Date    account
9/8/2020    555
9/8/2020    666
9/8/2020    777
9/8/2020    888
9/9/2020    555
9/9/2020    999
9/10/2020   555
9/10/2020   222
9/10/2020   333
9/11/2020   666
9/11/2020   111

我想计算每天调用的唯一帐户的数量，并将其汇总一个月。例如，如果在9月8日、9月9日和9月20日调用了555帐户，则其总和不等于累计总和，结果如下所示

date    Cumulative Unique Accounts Called SO Far this month
9/8/2020    4
9/9/2020    5
9/10/2020   7
9/11/2020   8

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提前感谢您的帮助。

您可以使用聚合和窗口功能来完成此操作。首先，获取每个帐户的第一个日期，然后汇总和累积：

select min_date,
       count(*) as as_of_date,
       sum(count(*)) over (partition by year(min_datedate), month(min_datedate)
                           order by min_date
                          ) as cumulative_unique_count
from (select account, min(date) as min_date
      from t
      group by account, year(date), month(date)
     ) t
group by min_date;

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你可以试试下面的方法-

with cte as
(
select date,count(*) as total from
(
select date,count,row_number() over(partition by count order by date) as rn
from tablename
)A where rn=1 group by date
)

select date,sum(total) over(order by date) as cum_sum
from cte

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每天，甚至周末？