Sql Oracle-如何从子查询返回平均值?

Sql Oracle-如何从子查询返回平均值?,sql,oracle,group-by,Sql,Oracle,Group By,我需要选择工资高于按部门分组的平均工资的员工 SELECT * FROM employees WHERE salary > (SELECT AVG(salary), department_id FROM employees GROUP BY department_id) 它失败了,因为它返回了两列 我尝试了以下查询: SELECT * FROM employees HAVING salary > AVG(salary) GROUP BY (department_id) 现在我收到

我需要选择工资高于按部门分组的平均工资的员工

SELECT * FROM employees
WHERE salary > (SELECT AVG(salary), department_id FROM employees GROUP BY department_id)
它失败了,因为它返回了两列

我尝试了以下查询:

SELECT * FROM employees
HAVING salary > AVG(salary)
GROUP BY (department_id)

现在我收到错误消息:ORA-00979:不是一个groupby表达式

最简单的跨数据库方法是使用连接:

SELECT employees.*
FROM employees
JOIN ( SELECT department_id, AVG(salary) avgSalary
       FROM employees
       GROUP BY department_id) departmentSalaries
  ON employees.department_id = departmentSalaries.department_id
  AND employees.salary > departmentSalaries.avgSalary
Oracle最有效的方法是使用分析函数(也称为窗口函数):

SELECT * FROM (
  SELECT e.*, AVG(e.salary) OVER ( PARTITION BY e.department_id ) as avgSalary
  FROM employees e) t
WHERE salary > avgSalary