Sql Can'；Don’不要丢弃重复的

我有我的疑问：

SELECT   t.nCitiesId
    ,t.tmDate
    ,t.strShortWeekdayName
    ,t.nIsHoliday
FROM    #temp AS t
WHERE   1 = 1
AND     t.nCitiesId = 104
AND     t.tmDate = '2014-06-08'
GROUP BY t.tmDate, t.nCitiesId, t.strShortWeekdayName, t.nIsHoliday

这将产生以下结果：

nCitiesId         tmDate              strShortWeekdayName   nIsHoliday
104       2014-06-08 00:00:00.000            SUN                0
104       2014-06-08 00:00:00.000            SUN                1

我的问题是，当ncitiseid和tmDate相等时，我不希望nIsHoliday=0的那个消失了

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我如何才能使这一切顺利进行？

尝试使用having子句：

SELECT   t.nCitiesId
    ,t.tmDate
    ,t.strShortWeekdayName
    ,t.nIsHoliday
FROM    #temp AS t
WHERE   1 = 1
AND     t.nCitiesId = 104
AND     t.tmDate = '2014-06-08'
GROUP BY t.tmDate, t.nCitiesId, t.strShortWeekdayName, t.nIsHoliday
having max(t.nIsHoliday)

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选择具有最高值的t.nIsHoliday：

SELECT t.nCitiesId
      ,t.tmDate
      ,t.strShortWeekdayName
      ,max(t.nIsHoliday)
FROM   #temp AS t
WHERE  t.nCitiesId = 104
AND    t.tmDate = '2014-06-08'
GROUP BY t.nCitiesId, t.tmDate, t.strShortWeekdayName

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如果第三行的

nIsHoliday

=0，则希望该列的最终值为0或1？只要tmDate和nCitiesId相等，我只希望有一行。总是。nIsHoliday=1时