Sql 使用左连接获取所有日期
我正在尝试使用库存管理系统,在该系统中我必须跟踪产品的发布日期。因此,我的条件是-如果门店ID为1,年份为2014年,那么它应在该特定年份的发布日期之前退回所有产品,如下所示:Sql 使用左连接获取所有日期,sql,sql-server-2008,Sql,Sql Server 2008,我正在尝试使用库存管理系统,在该系统中我必须跟踪产品的发布日期。因此,我的条件是-如果门店ID为1,年份为2014年,那么它应在该特定年份的发布日期之前退回所有产品,如下所示: Product - Date - TotalIssued Keyboard - 2014-10-10 - 1 -- This product has been issued or given 1 time on that date of the year 2014 Mouse - 2014-10-11 - 1 K
Product - Date - TotalIssued
Keyboard - 2014-10-10 - 1 -- This product has been issued or given 1 time on that date of the year 2014
Mouse - 2014-10-11 - 1
Keyboard - 2014-10-12 - 0
Mouse - 2014-10-12 - 0
-------------------------
-------------------------
Keyboard - 2014-12-31 - 0
Mouse - 2014-12-31 - 0 -- This will continue till the end of the year
我尝试使用以下链接使用日历表,并创建了一个:
我使用以下查询使用日历表获得所需的输出,但它只返回已发布的产品,这意味着只返回存储在ReturnToStore表中的日期:
SELECT l.ItemName AS Product, m.PKDate AS Date, COUNT(m.PKDate) AS TotalIssued
FROM [days] m
LEFT JOIN ReturnToStore k ON CONVERT(DATE, k.IssuedDate) = m.PKDate
LEFT JOIN Item l ON l.ItemID = k.ItemID
WHERE m.calendar_year = 2014 AND k.StoreID = 1
GROUP BY k.StoreID, l.ItemName, m.PKDate
这是我现在得到的输出:
Product - Date - TotalIssued
Keyboard - 2014-10-10 - 1
Mouse - 2014-10-11 - 1
以下是表格结构:
CREATE TABLE [dbo].[Item](
[ItemID] [int] IDENTITY(1,1) NOT NULL,
[ItemName] [varchar](50) NULL,
[Description] [varchar](150) NULL,
[Tag] [varchar](50) NULL,
CONSTRAINT [PK_Item] PRIMARY KEY CLUSTERED
(
[ItemID] ASC
)
) ON [PRIMARY]
INSERT INTO [dbo].[Item]
([ItemName]
,[Description]
,[Tag])
VALUES
('Keyboard', 'IT Equipment', ''),
('Mouse', 'IT Equipment', '')
CREATE TABLE [dbo].[ReturnToStore](
[ID] [int] IDENTITY(1,1) NOT NULL,
[StoreID] [int] NULL,
[CategoryID] [int] NULL,
[ItemID] [int] NULL,
[Quantity] [float] NULL,
[IssuedDate] [datetime] NULL,
[Description] [varchar](150) NULL,
[OrderID] [varchar](50) NULL,
CONSTRAINT [PK_ReturnToStore] PRIMARY KEY CLUSTERED
(
[ID] ASC
)
) ON [PRIMARY]
INSERT INTO [dbo].[ReturnToStore]
([StoreID]
,[CategoryID]
,[ItemID]
,[Quantity]
,[IssuedDate]
,[Description]
,[OrderID])
VALUES
(1, 1, 1, 10, '2014-10-10 00:00:00.000', '', 'PO-02'),
(1, 1, 2, 20, '2014-10-11 00:00:00.000', '', 'PO-03')
**Note:** I guess, this could be done easily with LEFT JOIN using calendar table. But got stuck here.
已编辑:我已更新帖子,因为我已使用以下内容将查询转换为pivot:
CREATE PROCEDURE [dbo].[MonthlyConsumption]
@StoreID int,
@Year int
AS
SELECT Distinct ItemName,
[1] AS M1,
[2] AS M2,
[3] AS M3,
[4] AS M4,
[5] AS M5,
[6] AS M6,
[7] AS M7,
[8] AS M8,
[9] AS M9,
[10] AS M10,
[11] AS M11,
[12] AS M12
FROM
(SELECT MONTH(m.PKDate) as YEAR,
p.ItemName, k.IssuedDate, k.ItemID
FROM [days] m
CROSS JOIN (SELECT DISTINCT itemName,itemID FROM Item) p
LEFT JOIN ReturnToStore k
ON CONVERT(DATE, k.IssuedDate) = m.PKDate AND
p.itemid = k.itemid AND
k.StoreID = @StoreID
LEFT JOIN Item l
ON l.ItemID = k.ItemID
WHERE m.calendar_year = @Year
GROUP BY p.ItemName, m.PKDate, k.ItemID, k.IssuedDate)
source
PIVOT
(
COUNT(ItemID)
FOR YEAR
IN ( [1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12])
) AS PivotDay
返回以下输出:
我不知道为什么会重复,如果我在特定日期多次添加相同的产品,那么透视图中不会显示任何更改,并且与给定的输出保持不变。我不确定这是否是解决方案,但至少这是一个改进 当
LEFT JOIN
时,将右侧表的条件放入ON
子句中,以获得trueLEFT JOIN
行为。(在WHERE
中时,您将获得常规的内部联接
结果。)即将k.StoreID=1移动到ON
子句:
SELECT l.ItemName AS Product, m.PKDate AS Date, COUNT(m.PKDate) AS TotalIssued
FROM [days] m
LEFT JOIN ReturnToStore k ON CONVERT(DATE, k.IssuedDate) = m.PKDate AND k.StoreID = 1
LEFT JOIN Item l ON l.ItemID = k.ItemID
WHERE m.calendar_year = 2014
GROUP BY l.ItemName, m.PKDate
您的第一个错误是,您在WHERE
子句中的LEFT JOIN
的右表上放置了一个条件,而不是on
子句
第二件事,您还应该为项目名称使用派生表,就像日期一样:
SELECT p.ItemName AS Product, m.PKDate AS Date, COUNT(l.ItemID) AS TotalIssued
FROM [days] m
CROSS JOIN (SELECT DISTINCT itemName,itemID FROM Item) p
LEFT JOIN ReturnToStore k
ON CONVERT(DATE, k.IssuedDate) = m.PKDate AND
p.itemid = k.itemid AND
k.StoreID = 1
LEFT JOIN Item l
ON l.ItemID = k.ItemID
WHERE m.calendar_year = 2014
GROUP BY p.ItemName, m.PKDate
查询成功,但它没有显示未发布日期的产品名称,对于TotalIssuited列,它显示所有日期的1。成功,但对于TotalIssuited列,它始终显示所有日期的1。如果在该年的特定日期没有发布任何产品,则TotalIssuited列将为0。是的,需要从右表中计算不同的列。现在试试@AT-2016,效果很好。非常感谢@sagi。一切都很好@sagi,但最后一件事。我编辑了这篇文章。如果你能看到帖子,请告诉我。谢谢。@AT-2016这是一个不同的问题,你应该打开一个新的帖子。我不太擅长旋转。