SQLite基于where子句选择下一行和上一行

我希望能够使用SQLite获取下一行和上一行

id  statusid  date
168 1   2010-01-28 16:42:27.167
164 1   2010-01-28 08:52:07.207
163 1   2010-01-28 08:51:20.813
161 1   2010-01-28 07:10:35.373
160 1   2010-01-27 16:09:32.550
 46 2   2010-01-30 17:13:45.750
145 2   2010-01-30 17:13:42.607
142 2   2010-01-30 16:11:58.020
140 2   2010-01-30 15:45:00.543

例如：

给定id 46，我想返回上一个id 160，下一个id 145

给定ID160，我想将ID161返回上一个，将ID46返回下一个 等等

请注意，数据是按statusId排序的，然后按dateCreated DESC排序的，必须使用SQLite

select * from @t order by statusId, dateCreated desc

在sql server中创建的测试数据

set nocount on; set dateformat ymd;
declare @t table(id int, statusId int, dateCreated datetime)
insert into @t
select 168,1,'2010-01-28 16:42:27.167' union
select 164,1,'2010-01-28 08:52:07.207' union
select 163,1,'2010-01-28 08:51:20.813' union
select 161,1,'2010-01-28 07:10:35.373' union
select 160,1,'2010-01-27 16:09:32.550' union
select  46,2,'2010-01-30 17:13:45.750' union
select 145,2,'2010-01-30 17:13:42.607' union
select 142,2,'2010-01-30 16:11:58.020' union
select 140,2,'2010-01-30 15:45:00.543'

使用SQLServer2005+这将非常简单

编辑：

这是相同的测试数据脚本，但用于SQLite，这是问题的焦点

create table t (id int, statusId int, dateCreated datetime);
insert into t
select 168,1,'2010-01-28 16:42:27.167' union
select 164,1,'2010-01-28 08:52:07.207' union
select 163,1,'2010-01-28 08:51:20.813' union
select 161,1,'2010-01-28 07:10:35.373' union
select 160,1,'2010-01-27 16:09:32.550' union
select  46,2,'2010-01-30 17:13:45.750' union
select 145,2,'2010-01-30 17:13:42.607' union
select 142,2,'2010-01-30 16:11:58.020' union
select 140,2,'2010-01-30 15:45:00.543';

---

编辑2请注意，数据不是一个很好的示例，因此我已将id 146更改为46

此问题比最初出现的问题复杂得多。这两个order by字段必须分别处理，然后与union组合并获取适当的结果。为了得到上一个和下一个，我们需要另一个工会，所以我们最终得到一个有子工会的工会

这适用于提供的数据。我测试了许多输入，得到了正确的上一个/下一个输出。使用时，请确保已获取所有要替换的146实例

SELECT *
FROM
(
    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid = t2.statusid
      AND   t1.dateCreated >= t2.dateCreated
      AND   t1.id <> 146

    UNION

    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid < t2.statusid


    ORDER BY             
            t1.statusid DESC,
            t1.dateCreated 

    LIMIT 1
)

UNION

SELECT *
FROM 
(
    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid = t2.statusid
      AND   t1.dateCreated <= t2.dateCreated
      AND   t1.id <> 146

    UNION

    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid > t2.statusid


    ORDER BY             
            t1.statusid,
            t1.dateCreated DESC

    LIMIT 1
)

ORDER BY             
        statusid,
        dateCreated DESC
;

---

它不是按id排序的，而是按状态id和日期排序的。Rippos在这样排序时没有说id是顺序的。@zapping，id不是顺序的，这是我的问题。对不起，这是不正确的。

SELECT *
FROM
(
    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid = t2.statusid
      AND   t1.dateCreated >= t2.dateCreated
      AND   t1.id <> 146

    UNION

    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid < t2.statusid


    ORDER BY             
            t1.statusid DESC,
            t1.dateCreated 

    LIMIT 1
)

UNION

SELECT *
FROM 
(
    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid = t2.statusid
      AND   t1.dateCreated <= t2.dateCreated
      AND   t1.id <> 146

    UNION

    SELECT  t1.*
    FROM    t t1,
            (
                SELECT  *
                FROM    t
                WHERE   id = 146
            ) t2
    WHERE   t1.statusid > t2.statusid


    ORDER BY             
            t1.statusid,
            t1.dateCreated DESC

    LIMIT 1
)

ORDER BY             
        statusid,
        dateCreated DESC
;