Mysql查询记录中的问题

查询：

我有两张唱片第一张唱片的名字是

SELECT t1.id,
       t1.ads_city,
       t1.ads_title,
       t1.ads_description,
       t1.ads_type,
       t2.ads_activate,
       t2.postads_id,
       t2.ads_id 
  FROM table_1 t1 
  JOIN nextpostads t2 ON t1.id = t2.postads_id
 WHERE MATCH(t1.ads_title,t1.ads_description) AGAINST ('LCD  projector ,' IN BOOLEAN MODE)  
   AND t2.ads_activate='Yes' 
   AND t1.ads_type='offering'

" LCD projector,plasma display,recording speaker products"

第二个记录标题是

SELECT t1.id,
       t1.ads_city,
       t1.ads_title,
       t1.ads_description,
       t1.ads_type,
       t2.ads_activate,
       t2.postads_id,
       t2.ads_id 
  FROM table_1 t1 
  JOIN nextpostads t2 ON t1.id = t2.postads_id
 WHERE MATCH(t1.ads_title,t1.ads_description) AGAINST ('LCD  projector ,' IN BOOLEAN MODE)  
   AND t2.ads_activate='Yes' 
   AND t1.ads_type='offering'

" LCD projector,plasma display,recording speaker products"

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但从上面的查询中，我不知道结果有什么问题？

我猜是

t2。ads\u activate

值不是“是”和/或

t1。ads\u type

值不是“提供”。尝试：

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如果返回了预期的记录，请添加缺少的WHERE子句，一次测试一个。否则，您的加入有问题…

您从这个查询中得到了什么结果，请给出一些示例data@Ajay_kumar当前位置如果这有助于回答您的问题，您介意将其标记为答案吗？单击答案左侧数字（当前为零）和箭头下方的复选图标。