Sql 在Oracle中显示（2015年1月1日）到今天之间的所有日期

这是我的

with 
a as
(select 1 as k, to_date('01/01/2015', 'mm/dd/yyyy') as temp from dual),
b as
(select 1 as k, sysdate as t from dual)

select * from a
join b on a.k = b.k
where a.temp between a.temp and b.t

现在，我想显示这两个日期之间的所有日期

我如何生成它

最好的，

你离得太近了

with 
a as
(select 1 as k, to_date('01/01/2015', 'mm/dd/yyyy') as temp from dual),
b as
(select 1 as k, sysdate as t from dual)
select a.temp + level - 1 result from a          --> this
join b on a.k = b.k
where a.temp between a.temp and b.t
connect by level <= b.t - a.temp + 1;            --> this

结果是

RESULT                                                                          
----------                                                                      
01/01/2015                                                                      
02/01/2015                                                                      
03/01/2015                                                                      
04/01/2015 

<snip>

28/10/2019
29/10/2019
30/10/2019
31/10/2019

1765 rows selected.

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