Sql 查询与基于第一个查询的另一个查询的并集
我想要一个带有连接的查询和另一个使用第一个查询的输出作为输入的查询的并集 我试着创建一个存储过程，通过游标循环，并在临时表中逐个插入数据，但速度非常慢。如果你想看一下程序，请告诉我 我的第一个问题是：Sql 查询与基于第一个查询的另一个查询的并集,sql,oracle,Sql,Oracle,我想要一个带有连接的查询和另一个使用第一个查询的输出作为输入的查询的并集 我试着创建一个存储过程，通过游标循环，并在临时表中逐个插入数据，但速度非常慢。如果你想看一下程序，请告诉我 我的第一个问题是： SELECT od.ID, od.CUST_PO_NUM, od.CUST_STATUS, TO_CHAR(od.SHIP_DATE,'DD-MON-YY') AS SHIP_DATE, od.A_PART_NUM, TO_CHAR(REQUIRED_DATE,'DD-MON-
SELECT od.ID,
od.CUST_PO_NUM,
od.CUST_STATUS,
TO_CHAR(od.SHIP_DATE,'DD-MON-YY') AS SHIP_DATE,
od.A_PART_NUM,
TO_CHAR(REQUIRED_DATE,'DD-MON-YY') AS REQUIRED_DATE,
SUM(NVL(ct.SHIPPED_QTY, 0)) AS SHIPPED_QTY,
TO_CHAR(od.CUR_ACKED_DATE,'DD-MON-YY') AS CUR_ACKED_DATE,
TO_CHAR(od.DOCK_DATE,'DD-MON-YY') AS DOCK_DATE,
TO_CHAR(od.POD_DATE,'DD-MON-YY') AS POD_DATE,
od.SHIP_TO,
od.UNIT_PRICE,
od.ITEM_TOTAL,
od.SHIP_FROM,
od.REQUIRED_DATE_LASTCHG_DT,
od.DOCK_DATE_LASTCHG_DT,
od.CUST_STATUS_LASTCHG_DT,
od.ROUTING_CODE,
TO_CHAR(od.ENTERED_DATE,'DD-MON-YY') AS ENTERED_DATE,
od.CUST_NUM,
NVL(sd.SAD_ALERT_FLAG,'N') AS SAD_ALERT_FLAG,
NVL(sd.SHIP_ALERT,'N') AS SHIP_ALERT,
sd.person_id,
ct.DELIVERY_NUMBER,
ct.CR_TRACK_NUM,
NVL(od.CANCELLED_QUANTITY,'0') AS CANCELLED_QUANTITY,
ct.CARRIER_NAME,
ct.WAYBILL,
ct.SHIP_METHOD_CODE
FROM ORDER_DETAIL od,
ALERTS sd,
C_TRACKING ct
WHERE od.ID = sd.ID(+)
AND od.ID = ct.ID(+)
AND od.CUST_NUM IN (10000)
AND OD.CUST_STATUS in ( 'BOOKED', 'SCHEDULED TO SHIP', 'CLOSED' , 'CANCELLED' , 'INVOICE_HOLD')
GROUP BY od.ID,
od.CUST_PO_NUM,
od.CUST_STATUS,
od.SHIP_DATE,
od.A_PART_NUM,
od.REQUIRED_DATE,
od.CUR_ACKED_DATE,
od.DOCK_DATE,
od.POD_DATE,
od.SHIP_TO,
od.UNIT_PRICE,
od.ITEM_TOTAL,
od.SHIP_FROM,
od.REQUIRED_DATE_LASTCHG_DT,
od.DOCK_DATE_LASTCHG_DT,
od.CUST_STATUS_LASTCHG_DT,
od.ROUTING_CODE,
od.ENTERED_DATE,
od.CUST_NUM,
NVL(sd.SAD_ALERT_FLAG,'N'),
NVL(sd.SHIP_ALERT,'N'),
sd.person_id,
ct.DELIVERY_NUMBER,
ct.CR_TRACK_NUM,
NVL(od.CANCELLED_QUANTITY,'0'),
ct.CARRIER_NAME,
ct.WAYBILL,
od.CUST_NUM,
ct.SHIP_METHOD_CODE
ORDER BY od.CUST_PO_NUM ASC
query1query1order\u detailparent\u line\u numberquery1SELECT ID,
CUST_PO_NUM,
CUST_STATUS,
TO_CHAR(SHIP_DATE,'DD-MON-YY') AS SHIP_DATE,
A_PART_NUM,
TO_CHAR(REQUIRED_DATE,'DD-MON-YY') AS REQUIRED_DATE,
NULL,
TO_CHAR(CUR_ACKED_DATE,'DD-MON-YY') AS CUR_ACKED_DATE,
TO_CHAR(DOCK_DATE,'DD-MON-YY') AS DOCK_DATE,
TO_CHAR(POD_DATE,'DD-MON-YY') AS POD_DATE,
SHIP_TO,
UNIT_PRICE,
ITEM_TOTAL,
SHIP_FROM,
REQUIRED_DATE_LASTCHG_DT,
DOCK_DATE_LASTCHG_DT,
CUST_STATUS_LASTCHG_DT,
ROUTING_CODE,
TO_CHAR(ENTERED_DATE,'DD-MON-YY') AS ENTERED_DATE,
CUST_NUM,
NULL,
NULL,
Null,
NULL,
NULL,
NVL(CANCELLED_QUANTITY,'0') AS CANCELLED_QUANTITY,
NULL,
NULL,
NULL,
parent_line_number,
chip_set_flag,
NULL,
NULL,
Null,
NULL,
NULL,
WAREHOUSE
FROM ORDER_DETAIL where parent_line_number in (select Id from query1) ;
id column1 cloumn2 ..... parent_line_number
1 abc anj null
2 fff eee null
3 bbb www 1
4 abh nnn 1
5 amm ff 2
6 aaa ss 3
7 sss fff null
query1id column1 cloumn2 ..... parent_line_number
1 abc anj null
3 bbb www 1
4 abh nnn 1
7 sss fff null
如果我们能够以这样一种方式进行排序，它将显示第一个ID及其子数据，然后是第二个ID及其子数据，等等，那就太好了。尝试使用
withWITH first_query AS(
SELECT .... first query goes here
...
...
)
SELECT ........
.... second query goes here ....
.....
WHERE parent_line_number in (select Id from first_query)
UNION ALL
SELECT * FROM first_query
尝试使用
withWITH first_query AS(
SELECT .... first query goes here
...
...
)
SELECT ........
.... second query goes here ....
.....
WHERE parent_line_number in (select Id from first_query)
UNION ALL
SELECT * FROM first_query
稍微扩展Kordiko的答案，使用简化的示例数据：
with query1 as (
select id, column1, column2, parent_line_number
from order_detail
where id in (1, 7)
)
select id, column1, column2, parent_line_number
from query1
union all
select o.id, o.column1, o.column2, o.parent_line_number
from query1 q1
join order_detail o on o.parent_line_number = q1.id;
ID COL COL PARENT_LINE_NUMBER
---------- --- --- ---------------------------------------
1 abc anj
7 sss fff
3 bbb www 1
4 abh nnn 1
with query1 as (
select id, column1, column2, parent_line_number
from order_detail
where id in (1, 7)
)
select id, column1, column2, parent_line_number
from (
select id, column1, column2, parent_line_number, id as ord1, 0 as ord2
from query1
union all
select o.id, o.column1, o.column2, o.parent_line_number, q1.id as ord1, 1 as ord2
from query1 q1
join order_detail o on o.parent_line_number = q1.id
)
order by ord1, ord2, id;
ID COL COL PARENT_LINE_NUMBER
---------- --- --- ---------------------------------------
1 abc anj
3 bbb www 1
4 abh nnn 1
7 sss fff
稍微扩展Kordiko的答案，使用简化的示例数据：
with query1 as (
select id, column1, column2, parent_line_number
from order_detail
where id in (1, 7)
)
select id, column1, column2, parent_line_number
from query1
union all
select o.id, o.column1, o.column2, o.parent_line_number
from query1 q1
join order_detail o on o.parent_line_number = q1.id;
ID COL COL PARENT_LINE_NUMBER
---------- --- --- ---------------------------------------
1 abc anj
7 sss fff
3 bbb www 1
4 abh nnn 1
with query1 as (
select id, column1, column2, parent_line_number
from order_detail
where id in (1, 7)
)
select id, column1, column2, parent_line_number
from (
select id, column1, column2, parent_line_number, id as ord1, 0 as ord2
from query1
union all
select o.id, o.column1, o.column2, o.parent_line_number, q1.id as ord1, 1 as ord2
from query1 q1
join order_detail o on o.parent_line_number = q1.id
)
order by ord1, ord2, id;
ID COL COL PARENT_LINE_NUMBER
---------- --- --- ---------------------------------------
1 abc anj
3 bbb www 1
4 abh nnn 1
7 sss fff
您使用的是哪个版本的Oracle？您确定在层次结构中只有一个级别-即父级和子级，但没有孙辈（或祖父母）？我使用的是11g。是的，不会有任何问题，您使用的是哪一版本的Oracle？您确定在层次结构中只有一个级别-即父级和子级，但没有孙辈（或祖父母）？我使用的是11g。是的，不会有孙子了。非常感谢，你让它看起来很简单：）有没有办法按照我上面描述的方式订购它们？非常感谢，你让它看起来很简单：）有没有办法按照我上面描述的方式订购它们？谢谢Alex。但这给了我两个问题。1：重复的数据，如果数据已经存在于连接的左侧和右侧。父行“”-数字显示的是id值，而不是原始值。有没有其他的方式来订购我的应用程序所需要的？很难说清楚你的意思。对于（1）您是否需要将查询1更改为添加
，并且父行编号为null父行\u编号，并且父行编号为null父行\u编号