Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/hibernate/5.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
处于Hibernate条件时的SQL案例_Sql_Hibernate_Hibernate Criteria - Fatal编程技术网

处于Hibernate条件时的SQL案例

处于Hibernate条件时的SQL案例,sql,hibernate,hibernate-criteria,Sql,Hibernate,Hibernate Criteria,当使用Hibernate条件创建else时,如何创建案例? 我的SQL是这样的: (CASE WHEN (SELECT COUNT(*) FROM EPS.RFQCORRIGENDUM WHERE RFQID=A.RFQ_ID AND STATUS='FINAL') > 0 THEN 'YES' ELSE 'NO' END) AS CORRIGENDUMISSUED 为什么不执行count查询,然后在Java代码中呈现y

当使用Hibernate条件创建else时,如何创建
案例?
我的SQL是这样的:

(CASE 
    WHEN 
        (SELECT COUNT(*) FROM EPS.RFQCORRIGENDUM 
        WHERE RFQID=A.RFQ_ID AND STATUS='FINAL') > 0 
    THEN 'YES' 
    ELSE 'NO' 
END) AS CORRIGENDUMISSUED

为什么不执行count查询,然后在Java代码中呈现yes或no?类似的问题: