Sql 将多行合并为一列中具有多个行值的行
我目前正在构建一个查询以从我的数据库中检索一些数据,我需要在一行中使用公共id访问一些信息 使用此查询:Sql 将多行合并为一列中具有多个行值的行,sql,postgresql,Sql,Postgresql,我目前正在构建一个查询以从我的数据库中检索一些数据,我需要在一行中使用公共id访问一些信息 使用此查询: select missions_answer.response_id as "response", crm_player."document" as "document", missions_question.label as "label", m
select
missions_answer.response_id as "response",
crm_player."document" as "document",
missions_question.label as "label",
missions_answertext.body as "bill #",
missions_answerselectmultiple.body as "product",
missions_answerinteger.body as "answer"
from missions_answer
left join missions_question on missions_answer.question_id = missions_question.id
left join missions_answertext on missions_answer.id = missions_answertext.answer_ptr_id
left join missions_answerselectmultiple on missions_answer.id = missions_answerselectmultiple.answer_ptr_id
left join missions_answerinteger on missions_answer.id = missions_answerinteger.answer_ptr_id
left join missions_response on missions_answer.response_id = missions_response.id
left join crm_player on missions_response.player_id = crm_player.id
LEFT JOIN crm_user ON crm_player.user_id = crm_user.id
where missions_answer.response_id = '71788176'
group by missions_answer.response_id, crm_player.document,missions_answertext.body,
missions_question.label,
missions_answerselectmultiple.body ,
missions_answerinteger.body,
crm_user.first_name,
crm_user.last_name
这就是我目前拥有的:
+ response + document + label + bill # + product + answer
- 71788176 - 79907201 - bill # - 26899 - -
- 71788176 - 79907201 - amount - - - 1
- 71788176 - 79907201 - product - - {"name": "Shoes"} -
- 71788176 - 79907201 - price - - - 25.99
这就是我要找的:
+ response + document + bill # + product + amount + price
- 71788176 - 79907201 - 26899 - shoes - 1 - 25.99
我一直在尝试使用
交叉表
,但我仍然找不到它,提前感谢您的任何提示或帮助。从您当前的状态,您只需使用过滤器
子句进行透视即可:
我不太清楚,你原来的桌子是什么样子的。如果是这样的话:
response | document | label | value
-------: | -------: | :------ | :----
71788176 | 79907201 | bill | 26899
71788176 | 79907201 | amount | 1
71788176 | 79907201 | product | shoes
71788176 | 79907201 | price | 25.99
然后,您可以按如下方式修改查询:
response | document | label | value
-------: | -------: | :------ | :----
71788176 | 79907201 | bill | 26899
71788176 | 79907201 | amount | 1
71788176 | 79907201 | product | shoes
71788176 | 79907201 | price | 25.99
编辑:要将JSON值添加到产品列: 变体1:您可以简单地将类型
json
转换为类型text
:
MAX(product::text) FILTER (WHERE label = 'product') as product,
变量2:从“name”
属性读取值:
MAX(product ->> 'name') FILTER (WHERE label = 'product') as product,
一个响应总是只包含一个产品吗?非常感谢您的回答,我在将MAX应用于包含该产品的JSON单元格时遇到了一个错误,知道吗?必须对JSON进行稍微不同的处理。请编辑您的问题并附加一些实际输入数据。JSON数据在哪里,它看起来怎么样,您期望的输出是什么
MAX(product ->> 'name') FILTER (WHERE label = 'product') as product,