Sql 中的PIVOT函数返回所有零

我有一张如下表：

TestCaseID  |  currentResultVerdict
    1                Passed
    2                Failed
    3                Blocked
    4                Blocked
    5                Inprogress
    6                Passed
    7                Passed

select  *
from
(select TestCaseID, currentResultVerdict from R_4_TestCases) As SourceTable
PIVOT
(
count(TestCaseID)
for currentResultVerdict in (['Passed'],['Failed'],['Blocked'],['Inprogress'])
) As PivotTabe

我想产生如下结果：

Passed | Failed | Blocked | Inprogress
  3         1        2          1

我使用了

PIVOT

查询，如下所示：

TestCaseID  |  currentResultVerdict
    1                Passed
    2                Failed
    3                Blocked
    4                Blocked
    5                Inprogress
    6                Passed
    7                Passed

select  *
from
(select TestCaseID, currentResultVerdict from R_4_TestCases) As SourceTable
PIVOT
(
count(TestCaseID)
for currentResultVerdict in (['Passed'],['Failed'],['Blocked'],['Inprogress'])
) As PivotTabe

我的输出是：

'Passed' | 'Failed' | 'Blocked' | 'Inprogress'
  0           0          0            0

为什么我得到零

---

为了便于阅读，我没有在我的表中包括其他列

作为

pivot

的替代方法。您可以通过条件聚合获得相同的结果：

declare @tmp table (TestCaseID  int,  currentResultVerdict varchar(50))
insert into @tmp
values
 (1, 'Passed')
,(2, 'Failed')
,(3, 'Blocked')
,(4, 'Blocked')
,(5, 'Inprogress')
,(6, 'Passed')
,(7, 'Passed')

select 
     sum (case when currentResultVerdict='Passed'     then 1 else 0 end) as Passed
    ,sum (case when currentResultVerdict='Failed'     then 1 else 0 end) as Failed
    ,sum (case when currentResultVerdict='Blocked'    then 1 else 0 end) as Blocked
    ,sum (case when currentResultVerdict='Inprogress' then 1 else 0 end) as Inprogress
from @tmp

结果:

---

作为

pivot

的替代方案，您可以通过条件聚合实现相同的结果：

declare @tmp table (TestCaseID  int,  currentResultVerdict varchar(50))
insert into @tmp
values
 (1, 'Passed')
,(2, 'Failed')
,(3, 'Blocked')
,(4, 'Blocked')
,(5, 'Inprogress')
,(6, 'Passed')
,(7, 'Passed')

select 
     sum (case when currentResultVerdict='Passed'     then 1 else 0 end) as Passed
    ,sum (case when currentResultVerdict='Failed'     then 1 else 0 end) as Failed
    ,sum (case when currentResultVerdict='Blocked'    then 1 else 0 end) as Blocked
    ,sum (case when currentResultVerdict='Inprogress' then 1 else 0 end) as Inprogress
from @tmp

结果:

---

方括号内不应包含单引号。应该是这样的<代码>['Passed']将匹配以单个字符开头和结尾的字符串quote@MartinSmith就这样！。谢谢你的帮助。删除单引号将返回所需结果。不应将单引号包含在方括号内。应该是这样的<代码>['Passed']将匹配以单个字符开头和结尾的字符串quote@MartinSmith就这样！。谢谢你的帮助。删除单引号现在会返回所需的结果。