如何在sql中在单个查询中组合两个结果

我有这个疑问

Select
     Count(IN_Invoices.in_id) NoOfInv,
     sum(in_total) AMTsum,
     CLOI_ClientOrderItems.cl_Id     
from
(
    select
        distinct MasterOrderId,
        cl_Id 
    from CLOI_ClientOrderItems
 ) as CLOI_ClientOrderItems 
inner Join IN_Invoices 
  on IN_Invoices.MasterOrderId=CLOI_ClientOrderItems.MasterOrderId
group by CLOI_ClientOrderItems.cl_id

查询结果为

noofinc amtsum cl_id 7 245 100000pri 247 181110.29 100001pro 在这个查询中，我输入了月份，因此它会显示该月份的记录

noofinc amtsum cl_id Grandtotal 5 7.00 100000_Pri 7.00 12 2510.12 100001_pro 2510.12 noofinc amtsum cl_id Grandtotal 5 7.00 100000_Pri 7.00 12 2510.12 100001_pro 2510.12 但在此查询结果中，如果我输入了月份，则显示错误，也应显示该结果（请参见AMSUM列的第一个查询结果） 格兰道尔是

245 181110.29 245 181110.29

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确定记录是否在所需月份的用例。选择所有记录（no where子句），并使用该大小写表达式决定是添加值还是忽略值。在下面的示例中，我构建了一个flag month_匹配以增强可读性。为此，我必须首先构建一个子查询。没有必要；我只是更喜欢这样

select 
  cl_id,
  sum( case when month_match = 1 then 1 else 0 end ) as count_invoices_in_month,
  sum( case when month_match = 1 then in_total else 0 end ) as sum_invoices_in_month,
  count(*) as count_invoices_total,
  sum( in_total ) as sum_invoices_total
from
(
  select
    i.in_id,
    i.in_total,
    cloi.cl_id,
    case when datepart(mm, i.in_date_issued) = 1
         and datepart(yyyy, i.in_date_issued) = 2014 then
      1
    else
      0
    end as month_match
  from
  (
    select distinct masterorderid, cl_id from cloi_clientorderitems
  ) as cloi
  inner join in_invoices i on i.masterorderid=cloi.masterorderid
)
group by cl_id;

---

第二个查询无法显示提到的结果，因为它的选择列表中有3列，而不是结果中提到的4列。在上一个查询结果amtsum列中，我需要将它添加到第二个查询中，您使用的是哪个

RDBMS

？请不要反复发布相同的问题。它的给出错误“关键字“group”附近的语法不正确。”

select 
  cl_id,
  sum( case when month_match = 1 then 1 else 0 end ) as count_invoices_in_month,
  sum( case when month_match = 1 then in_total else 0 end ) as sum_invoices_in_month,
  count(*) as count_invoices_total,
  sum( in_total ) as sum_invoices_total
from
(
  select
    i.in_id,
    i.in_total,
    cloi.cl_id,
    case when datepart(mm, i.in_date_issued) = 1
         and datepart(yyyy, i.in_date_issued) = 2014 then
      1
    else
      0
    end as month_match
  from
  (
    select distinct masterorderid, cl_id from cloi_clientorderitems
  ) as cloi
  inner join in_invoices i on i.masterorderid=cloi.masterorderid
)
group by cl_id;